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puteri [66]
3 years ago
14

How do you solve -.18 ÷ .03

Mathematics
2 answers:
Alex777 [14]3 years ago
5 0
<span>-.18 ÷ .03
answer is -6

</span>
meriva3 years ago
5 0
The answer is - 6 !!!!!
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Given that ABCD is a trapezoid (AB ∥ DC), AD = BD = CD = 6.5cm and BC = 5cm. Find the length of the diagonal
skelet666 [1.2K]
It will be ad k i hope i am right
3 0
3 years ago
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Kaylee earned $446.40 at her job when she worked for 18 hours. What was her hourly wage, in dollars per hour?
FinnZ [79.3K]

Answer:

Kaylee earned $24.8 per minute.

Step-by-step explanation:

Basically, just divide the total wage, by hours earned.

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7 0
3 years ago
find the equation of the line that is perpendicular to the given line and passes through the given point. CD; (-2,1). C cornet p
Studentka2010 [4]

Answer:

  x -2y = -4

Step-by-step explanation:

The slope of the line between points C and D is ...

  m = (y2 -y1)/(x2 -x1)

  m = (7 -13)/(5 -2) = -6/3 = -2

The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...

  y -k = m(x -h) . . . . line with slope m through point (h, k)

  y -1 = 1/2(x -(-2))

We can rearrange this to standard form.

  2y -2 = x +2 . . . . . multiply by 2

  -4 = x -2y . . . . . . . subtract 2y+2

  x -2y = -4 . . . . . . standard form equation of the desired line

5 0
2 years ago
Consider the incomplete paragraph proof. given: isosceles right triangle xyz (45°–45°–90° triangle) prove: in a 45°–45°–90° tria
mash [69]

1. We have to prove that in a 45°–45°–90° isosceled triangle, the hypotenuse is times the length of each leg.

2. Since, triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, which states a^2+b^2=c^2

But, in isosceles triangle it becomes 

a^2+a^2=c^2

3. By combining like terms, we get

2a^2=c^2

4. Now, we will determine the principal square root of both sides of the equation.

\sqrt2 a = c

5. Dividing both sides of the equation by '2', we get

\frac{a}{\sqrt 2} = \frac{c}{2}

a = \frac{c}{\sqrt 2}

So, c = \sqrt{2}a

6. So the hypothenuse c is \sqrt 2  times the length of each leg 'a'.

6 0
4 years ago
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Proof 1<br> Given: AB║CD , AD║CB<br> Prove: ΔABC ≅ΔCDA
lys-0071 [83]

<u>Statement                                                  Reason                                             </u>

AB║CD , AD║CB                                      Given

m∠BAC = m∠ACD                                     Alternate Interior Angles

m∠ACB = m∠CAD                                     Alternate Interior Angles

AC = AC                                                      Reflexive Property of Equality

ΔABC ≅ΔCDA                                            ASA ≅

7 0
3 years ago
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