Answer: I and III
Step-by-step explanation:
We observe in the case provided that the researcher, who has no interest in the population to intervene, is going to carry out surveys to assess whether the neighborhood is a good place to live, obtaining the following conclusions:
i. The Minneapolis Resident Survey was an observational study.
ii. The Minneapolis Resident Survey was an experiment.
iii. The figure 50.1% is a descriptive statistic for the sample.
iv. The figure 50.1% is a statistical inference for the population.:By estimating the sample, obtained by a lower percentage of the total of the respondents, it is known that with a 95% confidence interval that the rating obtained from the respondents considering that the neighborhood is a good place to live was found between 0.44 and 0.50, taking this interval as a statistical inference for the population.
The correct answer is I and III, since in this study no interventions were made to the population and only one observation of a characteristic of the neighborhood was made and in III we know that the descriptive statistic only describes data and summarizes it, which is a of the ways to display the data from the descriptive survey.
Answer:
7-4=3
6-2=4
-3-2= -5
-8+9=1
-9+5= -4
1+10=11
Step-by-step explanation:
No es tan difícil, puedes g0oglearlo
The hight of the flag pole is i would say 44ft but i am not sure
Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of ![1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%20-%200.99%7D%7B2%7D%20%3D%200.905%28%5Btex%5Dt_%7B995%7D)
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Answer:
30/100
Step-by-step explanation:
This should be relatively easy since if the denominator is 100 then x/100 has to = 3/10
Since the denominator 10 has to be 100, you multiply by 10.
3 x 10 = 30
