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jolli1 [7]
2 years ago
15

What type of molecule are these and what is the strongest IMFs in between?​

Chemistry
1 answer:
Aneli [31]2 years ago
6 0

Answer:

CH2O is formaldehyde a covalent compound and its intermolecular forces are week

KCl is an ionic compound formed by electrostatic force of attraction between positive and negative charge. Ionic compounds also exists in three dimensional crystal lattic that is why intermolecular forces in KCl is stronger.

Moreover melting point of KCl is higher than CH2O

Explanation:

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Aqueous hydrochloric acid HCl reacts with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H
allochka39001 [22]

Answer : The theoretical yield of water formed from the reaction is 0.54 grams.

Solution : Given,

Mass of HCl = 1.1 g

Mass of NaOH = 2.1 g

Molar mass of HCl = 36.5 g/mole

Molar mass of NaOH = 40 g/mole

Molar mass of H_2O = 18 g/mole

First we have to calculate the moles of HCl and NaOH.

\text{ Moles of }HCl=\frac{\text{ Mass of }HCl}{\text{ Molar mass of }HCl}=\frac{1.1g}{36.5g/mole}=0.030moles

\text{ Moles of }NaOH=\frac{\text{ Mass of }NaOH}{\text{ Molar mass of }NaOH}=\frac{2.1g}{40g/mole}=0.525moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NaOH

So, 0.030 mole of HCl react with 0.030 mole of NaOH

From this we conclude that, NaOH is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of H_2O

From the reaction, we conclude that

As, 1 mole of HCl react to give 1 mole of H_2O

So, 0.030 moles of HCl react to give 0.030 moles of H_2O

Now we have to calculate the mass of H_2O

\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O

\text{ Mass of }H_2O=(0.030moles)\times (18g/mole)=0.54g

Therefore, the theoretical yield of water formed from the reaction is 0.54 grams.

6 0
3 years ago
The combined gas law states that
seropon [69]

Answer:

Option B. PV = nRT.

Explanation:

From the above,

C = PV / T. (1)

But, C is directly proportional to n, where R is the gas constant i.e

C & n

C = nR

Substituting the value of C into equation (1), we have:

C = PV / T

nR = PV / T

Cross multiply to express in linear form

nRT = PV

Therefore,

PV = nRT

8 0
2 years ago
Calculate the empirical formula of each of the following substances with the following compositions.
OleMash [197]

Explanation:

Note: Molar masses of elements can be found online or in the periodic table.

Moles of Magnesium

= 3.60g / (24.3g/mol) = 0.148mol.

Moles of Chlorine

= 10.65g / (35.45g/mol) = 0.300mol.

Mole ratio of Magnesium to Chlorine

= 0.148mol : 0.300mol = 1 : 2.

Hence we have the empirical formula MgCl2.

Moles of Lithium

= 9.1g / (6.94g/mol) = 1.311mol.

Moles of Oxygen

= 10.4g / (16g/mol) = 0.650mol.

Moles ratio of Lithium to Oxygen

= 1.311mol : 0.650mol = 2 : 1.

Hence we have the empirical formula Li2O.

7 0
2 years ago
Jennifer is applying a constant force to swing a can on the end of a string, as shown here. If the can is moving around the circ
Zepler [3.9K]

Answer:

Explanation:

D

4 0
3 years ago
Read 2 more answers
Two perfumes are released at the same time. If one is standing 7.5 m from the point of release. Perfume A (molar mass 275 g/mol)
natta225 [31]
According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".

                          rᵇ/rᵃ  =  \sqrt{da/db}
Or,
                          rᵇ/rᵃ  =  \sqrt{Ma/Mb}     ----- (1)
As, 
                          Ma  =  275 g/mol

                          Mb  =  205 g/mol

Putting Values in eq.1,

                          rᵇ/rᵃ  =  \sqrt{275/205}

                          rᵇ/rᵃ  =  1.15

Result:
          Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.
6 0
2 years ago
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