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lana [24]
3 years ago
7

What are the names of the stable forms of oxygen?

Chemistry
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

18 O, 17 O, and 16 O

Explanation:

three naturally stable isotopes

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For the reaction...
MAVERICK [17]

Answer:

A: Shift to the left

Explanation:

The reaction would try to use up the added heat by making more H 2 and Cl 2.

7 0
3 years ago
Fill in the missing piece of the table​
djyliett [7]

Answer: The final volume V_2 is 263.09 ml

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=156ml\\T_1=215^oC=(215+273)K=488K\\V_2=?\\T_2=550^0C=(550+273)K=823K

Putting values in above equation, we get:

\frac{156}{488}=\frac{V_2}{823}\\\\V_2=263.09ml

Thus final volume V_2 is 263.09 ml

5 0
3 years ago
How many elements make up Ibuprofen?<br><br> C13H18O2
mylen [45]

Answer:

Explanation:

wouldn't it be three because every capital is a new element?

3 0
2 years ago
The value of ksp for silver sulfide, ag2s, is 8.00×10−51. calculate the solubility of ag2s in grams per liter.
Ivanshal [37]
When Ag₂S dissolves, it dissociates as follows;
Ag₂S ---> 2Ag⁺ + S²⁻
First we need to calculate molar solubility which gives the number of moles dissolved in 1 L of solution.
If molar solubility of Ag₂S is y, then molar solubility of Ag²⁺ and S²⁻ is 2y and y respectively.
ksp gives the solubility constant
ksp = [Ag⁺]²[S²⁻]
ksp = [2y]²[y]
4y³ = 8.00 x 10⁻⁵¹ 
y³ = 2 x 10⁻⁵¹
y = 1.26 x 10⁻¹⁷ mol/L
molar mass = 247.8 g/mol
solubility of Ag₂S = 1.26 x 10⁻¹⁷ mol/L x 247.8 g/mol = 3.12 x 10⁻¹⁵ g/L 
Solubility of Ag₂S = 3.12 x 10⁻¹⁵ g/L 
7 0
4 years ago
Read 2 more answers
An unknown volume of gas has a pressure of 0.50 atm and temperature of 325 K. If the pressure is raised to 1.2 atm and the tempe
Grace [21]
You can solve this by using the equation (P1V1/T1) = (P2V2/T2). Plug in 0.50 atm for P1, leave V1 as the unknown, and plug in 325 K as T1. Then substitute 1.2 atm for P2, 48 L for V2, and 320 K for T2. Solve for V1, which is 117L, but since you round using two sig figs, your answer is C, 120 L. Hope this helps!
4 0
3 years ago
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