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marshall27 [118]
4 years ago
8

Energy + 6CO2 + 6H2O → 6O2 + C6H12O6 The purpose of photosynthesis is to produce usable chemical energy or glucose from solar en

ergy. If the formula for glucose is C6H12O6, how many atoms of carbon are used to produce the glucose?
A) 1

B) 2

C) 6

D) 9
Chemistry
2 answers:
Natalija [7]4 years ago
8 0

Answer:

The answer is c) 6

Explanation:

In the expression of the reaction  

Energy + 6CO2 + 6H2O → 6O2 + C6H12O6

you can see that to produce a mol of glucose (C6H12O6) you need 6 moles of CO2, which it is the reagent that contains the atom of carbon used to produce glucose. Now you multiply the coefficient 6 by the subscript 1, which is the amount of carbon atoms that the molecule CO2 contains. So you end up with <u><em>6 atoms of carbon.</em></u>

slava [35]4 years ago
7 0
C stands for carbon atoms. In glucose thera are 6 carbon atoms, so 6 carbon atoms are used to produce glucose.

Answer: C) 6
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A 7.06% aqueous solution of sodium bicarbonate has a density of 1.19g/mL at 25°C what is the molarity and molality of the soluti
lilavasa [31]

<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg

<em>Molar concentration </em>

Assume you have 1 L solution.

Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)

= 1190 g solution

Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)

= 84.01 g NaHCO3

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= 1.14 mol NaHCO3

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5 0
3 years ago
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An unknown compound containing only C and H was burnt, yielding 10.2 g of CO2 and 6.3 g of H2O. With a molecular weight of about
Lisa [10]

Answer:

C_2H_6

Explanation:

Hello.

In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:

m_C=10.2gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1mol C}{1molCO_2}=0.232 molC

Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:

m_H=6.3gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH_2}{1molH_2O}  =0.7molH

Then, to find the subscripts in the empirical formula, we divide by the moles of carbon as the smallest:

C:\frac{0.232}{0.232}=1\\ \\H:\frac{0.7}{0.232}=3

Whose molar mass is:

M_{CH_3}=12+1*3=15g/mol

Thus, the ratio of the molecular formula to the empirical formula is:

\frac{30}{15}=2

Therefore, the molecular formula is twice the empirical formula:

C_2H_6

Which is actually ethane.

Regards.

3 0
3 years ago
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