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marshall27 [118]
4 years ago
8

Energy + 6CO2 + 6H2O → 6O2 + C6H12O6 The purpose of photosynthesis is to produce usable chemical energy or glucose from solar en

ergy. If the formula for glucose is C6H12O6, how many atoms of carbon are used to produce the glucose?
A) 1

B) 2

C) 6

D) 9
Chemistry
2 answers:
Natalija [7]4 years ago
8 0

Answer:

The answer is c) 6

Explanation:

In the expression of the reaction  

Energy + 6CO2 + 6H2O → 6O2 + C6H12O6

you can see that to produce a mol of glucose (C6H12O6) you need 6 moles of CO2, which it is the reagent that contains the atom of carbon used to produce glucose. Now you multiply the coefficient 6 by the subscript 1, which is the amount of carbon atoms that the molecule CO2 contains. So you end up with <u><em>6 atoms of carbon.</em></u>

slava [35]4 years ago
7 0
C stands for carbon atoms. In glucose thera are 6 carbon atoms, so 6 carbon atoms are used to produce glucose.

Answer: C) 6
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Which boiling point is lower an why?
DiKsa [7]

Answer:4

Explanation:

If we carefully observe the electronegativity of the elements in question

P-2.19

N-3.04

C-2.55

Si-1.9

H-2.2

SiH4 is definitely more polar than CH4 hence greater dipole forces of a higher boiling point. NH3 is more polar than PH3 hence NH3 has greater dipole forces and a higher boiling point. Electronegative differences influences the polarity of a bond. The greater the electro negativity difference between bonding atoms, the greater the dipole forces and the greater the boiling point.

3 0
3 years ago
Read 2 more answers
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
How did knowing the number of valence electrons in one
Orlov [11]

Explanation:

Knowing the number of valence electrons in one of the alien elements helps in identifying it because the number of valence electrons can help categorize the alien element. Similar elements have the same valence electrons and knowing the category of the element can help further analyze the element.

5 0
3 years ago
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How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

8 0
3 years ago
What is the percent of copper in CuS?
bonufazy [111]

Answer:

Element Symbol Mass Percent

Cuprum Cu 66.464%

Sulfur S 33.537%

Explanation:

I got this out of my module, sorry if it's wrong but i am pretty sure 97% this is correct!

7 0
3 years ago
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