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marshall27 [118]
3 years ago
8

Energy + 6CO2 + 6H2O → 6O2 + C6H12O6 The purpose of photosynthesis is to produce usable chemical energy or glucose from solar en

ergy. If the formula for glucose is C6H12O6, how many atoms of carbon are used to produce the glucose?
A) 1

B) 2

C) 6

D) 9
Chemistry
2 answers:
Natalija [7]3 years ago
8 0

Answer:

The answer is c) 6

Explanation:

In the expression of the reaction  

Energy + 6CO2 + 6H2O → 6O2 + C6H12O6

you can see that to produce a mol of glucose (C6H12O6) you need 6 moles of CO2, which it is the reagent that contains the atom of carbon used to produce glucose. Now you multiply the coefficient 6 by the subscript 1, which is the amount of carbon atoms that the molecule CO2 contains. So you end up with <u><em>6 atoms of carbon.</em></u>

slava [35]3 years ago
7 0
C stands for carbon atoms. In glucose thera are 6 carbon atoms, so 6 carbon atoms are used to produce glucose.

Answer: C) 6
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Answer:

The atomic mass number is the number of protons and neutrons in an atom.

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Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio
umka21 [38]

Answer : The value of K_p at this temperature is 66.7

Explanation : Given,

Pressure of PCl_3 at equilibrium = 0.348 atm

Pressure of Cl_2 at equilibrium = 0.441 atm

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The balanced equilibrium reaction is,

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}

Now put all the values in this expression, we get :

K_p=\frac{(10.24)}{(0.348)(0.441)}

K_p=66.7

Therefore, the value of K_p at this temperature is 66.7

4 0
2 years ago
What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?
Sever21 [200]

Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

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Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}

x = 295.7 mL

295.7 mL of 24% trichloroacetic acid (tca) is needed .

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