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3 years ago

Explain the relationship between the relative size of an ion and its neutral atom and the charge on the ions

Chemistry

1 answer:

mars1129 [50]3 years ago

3 0

A cation (+) will be smaller than its neutral atom, while anion (-) will be larger than its neutral atom.

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How many oxygen atoms are there in the following compound: 2HNO3<br> 3<br> 5<br> 6<br> 12

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Explanation:

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I. Give the name for the following compounds:

alexandr402 [8]

Answer:

Explanation:

1) MgBr₂

Magnesium bromide

2) Ca₃(PO₄)₂

Calcium phosphate

3) NO₂

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4) Ni₂(CO₃)₃

Nickel(III) carbonate

5) (NH₄)₂CO₃

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6) MnBr₂

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7) Na[MnO₄]

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3 years ago

Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT

Andru [333]

Answer:

$6.14\cdot 10^{-6}$

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

$\Delta G^o = -RT ln K_{eq}$

From here, rearrange the equation to solve for K:

$K_{eq} = e^{-\frac{\Delta G^o}{RT}}$

Now we know from the initial equation that:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Let's express the ratio of ADP to ATP:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}$

Substitute the expression for K:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}$

Now we may use the values given to solve:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}$

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4 years ago