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2 years ago

Margaret has some cows. The cows produce an average total of 11.9

Mathematics

1 answer:

Leokris [45]2 years ago

8 0

Answer:

6902

Step-by-step explanation:

Total milk produced in 290 days = 11.9 x 290 = 3451 litres

If 1 bottle has a capacity of 0.5l, the number of bottles needed = 3451 / 0.5 = 6902 bottles

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Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago

A set of composite numbers less than 12 .express it in listing and set builder methods

marusya05 [52]

Given:

A set of composite numbers less than 12.

To find:

The set by listing and set builder methods.

Solution:

Composite number: A positive integer is called a composite number if it has at least one divisor other than 1 and itself.

Composite numbers less than 12 are 4, 6, 8, 9, 10.

By using the listing method , the given set can be expression as:

Set = {4, 6, 8, 9, 10}

The numbers 4, 6, 8, 9, 10 are greater than 1, less than 12 and non prime numbers.

By using set builder method, the given set can be expression as:

Set = $\{x|x\neq P,1$

Therefore, the list and set builder notation of the given set are {4, 6, 8, 9, 10} and $\{x|x\neq P,1$ respectively.

5 0

2 years ago

GIVING BRAIN AND 30pointsWhat is the solution to the system of equations below?

SpyIntel [72]

Answer:

No solution

Step-by-step explanation:

Using substitution, we get to the answer 12=0, which is untrue meaning no solution.

Hope this helps! Please give Brainliest!!

5 0

3 years ago

Read 2 more answers

. If Gene gets two more strikes (scores of 10), what is his new average?

dedylja [7]

I think u r sopost to multiply 10 times 2

3 0

2 years ago

Herman Melville had worked at the University Medical Center for 20 years when he became permanently disabled while at work. He c

lidiya [134]

Answer:

Herman Melville's annual disability benefit is $46,114.8

Step-by-step explanation:

Given the data in the question;

Herman Melville is 55 years, worked for 20 years, planned to retire in the next 10 years i.e at the age of 65.

so since he planned to work for the next 10 years;

total duration of work will be; ( 20 + 10) years = 30 years

Average salary per year = $76,908

Total salary in 30 years will be; $76,908 × 30 = $2,307,240

Hospital rate benefits = 2%

So, total annual disability benefit will be;

⇒ 2% of Total salary in 30 years

⇒ 2/100 × $2,307,240

= $46,114.8

Therefore, Herman Melville's annual disability benefit is $46,114.8

4 0

3 years ago