The sum of three consecutives is b
Answer: C
Hello,
Step-by-step explanation:
WZ=7-3=4
YW²=XW*WZ=3*4=12 ==> WY=2√3
In the right triangle YWZ, using the Pythagorean's theorem:
YZ²=WY²+WZ²=12+4²=28
YZ=2√7≅5.29150....
Answer C
Answer:
<h3>
9, 11, 13, 15</h3>
Step-by-step explanation:
{k - some integer}
2k+1 - the first odd integer (the least)
5(2k+1) - five times the least
5(2k+1)+3 -<u> three more than five times the least</u>
2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1
2k+3+2 = 2k+5 - the next odd consecutive integer (third)
2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)
2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>
2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3
8k + 16 = 10k + 5 + 3
- 10k -10k
-2k + 16 = 8
-16 - 16
-2k = -8
÷(-2) ÷(-2)
k = 4
2k+1 = 2•4+1 = 9
2k+3 = 2•4+3 = 11
2k+5 = 2•4+5 = 13
2k+7 = 2•4+7 = 15
Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1
Answer:
B
Step-by-step explanation:
Well you can get rid of c and d since 9^2 = 81. so 74 is less than 81 so it's definitely less than 9. Now, we know it's between 8 and 9. try multiplying 8.5 x 8.5 = 72.25. So our ranges are
A) 64 - 72.25
B) 72.25 - 81.
74 falls between 72.25 - 81. So it'll be B
