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const2013 [10]
3 years ago
6

How do i solve 2x=-3i need answer ASAP​

Mathematics
2 answers:
bekas [8.4K]3 years ago
4 0

Answer:

x=-1.5

Step-by-step explanation:

1. Divide on both sides to get the x alone; -3 divided by 2 is -.15 or -3/2

Mrrafil [7]3 years ago
3 0

Answer:

x = \frac{-3}{2} \\or \\x = -\frac{3}{2}\\or\\-1.5

Step-by-step explanation:

2x = -3

divide 2 from both sides

x = \frac{-3}{2} \\\\or \\x = -\frac{3}{2}

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A truck is said to get 18 miles per gallon on a highway, but this value can fluctuate,
Ratling [72]

Answer: 14 miles ≤ D ≤ 22 miles.

Step-by-step explanation:

The mean distance traveled per gallon, is 18 miles.

But this can fluctuate, at most, by 4 miles.

Because we have here the "at most", we know that we should use the ≤, ≥ symbols.

Then, if the mean is 18mi, the range of possible distances traveled per gallon is:

(18 miles - 4 miles) ≤ D ≤ (18 miles + 4 miles)

Where D is the distance.

14 miles ≤ D ≤ 22 miles.

So the truck can get between 14 miles and 22 miles per gallon on the highway.

4 0
3 years ago
Estimate the difference of the decimals below by rounding to the nearest
Olin [163]

Answer:

50

Step-by-step explanation:

53.042 -3.350 = 49.692---> 50

8 0
2 years ago
Read 2 more answers
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
8. Find the area of the regular polygon.​
Sliva [168]

Answer:

To find the area of a regular hexagon, or any regular polygon, we use the formula that says Area = one-half the product of the apothem and perimeter. As shown below, this means that we must find the perimeter (distance all the way around the hexagon) and the measure of the apothem using right triangles and trigonometry. Area of a Hexagon

Step-by-step explanation:

3 0
3 years ago
Hello everyone (this is 6th grade math)​
PtichkaEL [24]

Answer:

7 batches

Step-by-step explanation:

4 0
3 years ago
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