Answer:
D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.
Step-by-step explanation:
In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.
So it would appear as s ≥ 3g.
If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.
60 ≥ 3(20)
60 ≥ 60. These numbers make the linear system true.
If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.
2 to the power of 61 is = 2305843009213694000
then just minus that by 1 and divide it by 3. if it’s divisible then it’s a multiple of 3.
Answer:
Yes
Step by step explanation
Answer:
32/5
Step-by-step explanation:
K=Keep the first Fraction (You can rewrite 8 as 8/1 for when you multiply across.)
C=Change the Division Sign to a Multiplication Sign
F=Flip the Second Fraction
First, rewrite 1 1/4 as 5/4 (A mixed number can be changed to a fraction by multiplying the outside whole number by the denominator or bottom number of the fraction, then add the new rewritten whole number and the original fractional piece. In this case you would multiply the outside 1 by the bottom 4 and add it to the original 1/4. 4/4+1/4=5/4)
Second, Flip 5/4 to 4/5 and change your equation so it now reads: 8/1 x 4/5
Third, use simple fraction multiplication and multiply across to get 8/1 x 4/5=32/5
