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3 years ago

Tell me 5 things you have learned about scientific notation.... pls

1 answer:

6 0

Answer: 1) If the decimal is being moved to the right, the exponent is negative. 2) It’s it’s moved to the left, the exponent is positive.

Step-by-step explanation:

fnejfkenfejdb that’s all I know that is correct.

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Comparing freezers

zvonat [6]

Answer:

Freezer B has 8 more cubic feet than Freezer A.

Step-by-step explanation:

Volume of Freezer A = 8 * 4 * 2 = 64 ft^3.

Volume of Freezer B = 6 * 4 * 3 = 72 ft^3.

72 - 64 = 8 ft^3.

8 0

3 years ago

For a circle with a radius of 6 feet, what is the measurement of the central angle (in degrees) that intercepts an arc with a le

sp2606 [1]

<h3>The measurement of the central angle is 135 degrees</h3>

<em><u>Solution:</u></em>

<em><u>The length of arc when angle given in degrees is given as:</u></em>

$Arc\ length = \frac{ \theta }{360} \times 2 \pi r$

Where,

r is the radius

$\theta$ is the central angle in degrees

From given,

$r = 6\ feet\\\\Arc\ length = \frac{ 9 \pi }{2}\ feet$

Substituting the values we get,

$\frac{9 \pi }{2} = \frac{ \theta }{ 360} \times 2 \times \pi \times 6\\\\9 \times 360= \theta \times 24\\\\\theta = 135$

Thus the measurement of the central angle is 135 degrees

4 0

3 years ago

Which statement is true about the graph of

Alekssandra [29.7K]

The answer is C it’s vertex is at (2,4) because a quadratic formula is suppose to look like y= a ( x - h )^2 + k and the vertex is (h,k) when you look back at Your question h=-2 and but Bc of the formula then it’ll be h=2 and then k=4 and that’s how you get the vertex from a quadratic formula. Hope this helps :)

6 0

3 years ago

A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The

Oksanka [162]

Answer:

a) $[-0.134,0.034]$

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

$s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}$ ,

where $n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19$ .

The mean difference $\mu_1 - \mu_2 = 10.85 - 10.90 = -0.05$ .

The confidence interval is

$(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}$

$= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]$

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0

4 years ago

Pls help ASAP ‼️ will give brainliest

vlada-n [284]

Answer: 2592

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers