Answer:
ASA
Step-by-step explanation:
In the 2 triangles
∠J = ∠L
side OJ = side IL
∠O = ∠I
The triangles are congruent by the angle/side/angle (ASA ) postulate
Answer:
The value x in the equation 50=14+x+7+2x-1 is 10
Step-by-step explanation:
Given that the length of one side of a triangle is 14 inches
Let a be the length of one side
Therefore a=14 inches
The length of second side in x+7 inches
Let b be the length of second side
b=x+7 inches.
The length of third side is 2x-1 inches
Let c be the length of third side
c=2x-1 inches
And perimeter of the triangle =50 inches
Perimeter of a triangle =a+b+c
Equation can be written as
50=14+x+7+2x-1
50=20+3x ( adding the like terms )
Rewritting as below
3x+20=50
3x+20-50=50-50
3x-30=0
3x-30+30=0+30
3x=30

Therefore x=10
The value of x is 10
195 is divisible by 13 and 15
Hope this helped
Answer: find the solution in the explanation
Step-by-step explanation:
Let's use resolution of forces by resolving into x - component and y- component.
X - component.
Sum of forces = F1 - F3 - F4cos 15
Sum of forces = 0
5 - 5 - 0.97F4 = 0
- 0.97 F4 = 0
F4 = 0
Y - component
Sum of forces = F2 + F4 sin 15
Sum of forces = 0
5 + 0.26F4 = 0
0.26 F4 = -5
F4 = -5/0.26
F4 = -19.23 N
Simulating F4 back into the equation
Sum of forces = F1 - F3 - F4cos 15
- F4cos Ø = 0
- (-19.23) cos Ø = 0
Cos Ø = 0
Ø = 1
Does the angle formed approximate 15 degrees ? NO
Answer:
(x-5)²+(y-7)²=80
Step-by-step explanation: