a + b ≥ 30, b ≥ a + 10, the system of inequalities could represent the values of a and b
option A
<u>Step-by-step explanation:</u>
Here we have , The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is the greater integer, We need to find which system of inequalities could represent the values of a and b . Let's find out:
Let two numbers be a and b where b>a . Now ,
- The sum of two positive integers, a and b, is at least 30
According to the given statement we have following inequality :
⇒ 
- The difference of the two integers is at least 10
According to the given statement we have following inequality :
⇒ 
⇒ 
⇒ 
Therefore , Correct option is A) a + b ≥ 30, b ≥ a + 10
The answer is 9. because... (8+9) + 32= 49
Answer:
1
Step-by-step explanation:
None of these numbers are alike terms so the only number left is 1.
Answer:
In the picture I send above shows the step by step how to get the answers. Cheers!
S=Selling price 135
V=Variable cost 75
F=Fixed cost 3300
Let quantity be Q
The formula to break even is
135Q-75Q-3300=0
Solve for Q
60Q-3300=0
60Q=3300
Q=3300/60
Q=50
So the store must sell 50 bicycles to break even
Hope it helps!