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andrew-mc [135]
2 years ago
11

The quantity a varies directly with b and c and inversely with d. The quantity d is tripled. Which of the following must be true

for the relationship to remain the same? Both c and b must be tripled. The product of c and b must be tripled. Both c and b must be multiplied by 1/3. The product of c and b must be multiplied by 1/3.
Mathematics
1 answer:
Vinvika [58]2 years ago
8 0
Lets name the quantity Q
Q=k* \frac{b*c}{d} 

When quantity d is tripled, we get





Q=k \frac{b*c}{3d} 

To be the relationship the same, we see that we need to 
multiply  /numerator  / by  /3 


Q =  k \frac{3bc}{3d} 

So the answer should be 
"The product of c and b must be tripled."

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. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person
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Answer:

2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or greater?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater

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Please help thank you
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