Miguel's sister, Tara, has a checking account. Her bank charges a monthly

Mathematics

1 answer:

Tema [17]3 years ago

7 0

Answer:

True

Step-by-step explanation:

You might be interested in

Yeah i dont understand this-

Katyanochek1 [597]

You know each side is 9 meters long, meaning it’s a square. To find perimeter, add up all the sides aka. 9+9+9+9=36. To find the area, multiply one side by the other aka. 9x9 = 81.

7 0

3 years ago

Read 2 more answers

39 POINTS!! I NEED HELP ASAP!!!!!!! 2 QUESTIONS!!!!!

dangina [55]

Answer: 1) $A = 28ft^{2}$

2) 55 points

Step-by-step explanation:

1) A= 8w + 18, w=1.25

A = 8(1.25) + 18

A = 10 + 18

A = 28ft^2

2) 25 points to start with, additional 5 points per magazine they sell, m = number of magazines they sell

total points = 25 + 5m

How many if they sell 6?

total = 25 + 5(6)

= 25 + 30

total = 55

4 0

2 years ago

Read 2 more answers

Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.