3 years ago

Can someone please help with this? ;)

Chemistry

1 answer:

Anvisha [2.4K]3 years ago

3 0

Answer:

The correct answer is A

Explanation:

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Answer: The corresponding value of $K_p$ for this reaction at 84.5°C is 0.00232

Explanation:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

Relation of with is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

= equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = 0.0680

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

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Putting values in above equation, we get:

$K_p=0.0680\times (0.0821\times 357.5)^{-1}\\\\K_p=0.00232$

Thus the corresponding value of $K_p$ for this reaction at 84.5°C is 0.00232

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