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Zanzabum
2 years ago
13

There7 dogs and 7 rows how many are there

Mathematics
2 answers:
Novosadov [1.4K]2 years ago
8 0

Answer:

49 dogs

Step-by-step explanation:

an array of 7 dogs in 7 rows makes up 49 dogs.

7 times 7 is 49

faust18 [17]2 years ago
6 0

Answer:

7 x 7 = 49

Step-by-step explanation:

hope it helps, please mark as brainliest please

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Which is the percent for 1.67
Cloud [144]

Answer:

<h3>The answer is 167%</h3>

Step-by-step explanation:

<h3>Convert decimal to a percentage by multiplying the decimal by 100.</h3><h3>167%</h3>

<h3>I hope it helps you ❤❤❤</h3>
4 0
3 years ago
For the given position vectors r(t) compute the unit tangent vector T(t) for the given value of t .
algol13

Answer:

a) T(t) = \frac{}{5}=

T(4) =

b) T(t) = \frac{}{8\sqrt{37}}

T(4) =

c) T(t) = \frac{}{2425825977}

T(4) = \frac{1}{2425825977}

Step-by-step explanation:

The tangent vector is defined as:

T(t) = \frac{r'(t)}{|r'(t)|}

Part a

For this case we have the following function given:

r(t) =

The derivate is given by:

r'(t) =

The magnitude for the derivate is given by:

|r'(t)| = \sqrt{25 sin^2(5t) +25 cos^2 (5t)}= 5\sqrt{cos^2 (5t) + sin^2 (5t)} =5

And then the tangent vector for this case would be:

T(t) = \frac{}{5}=

And for the case when t=4 we got:

T(4) =

Part b

For this case we have the following function given:

r(t) =

The derivate is given by:

r'(t) =

The magnitude for the derivate is given by:

|r'(t)| = \sqrt{4t^2 +9t^4}= t\sqrt{4 + 9t^2}

|r'(4)| = \sqrt{4(4)^2 +9(4)^4}= 4\sqrt{4 + 9(4)^2} = 4\sqrt{148}= 8\sqrt{37}

And then the tangent vector for this case would be:

T(t) = \frac{}{8\sqrt{37}}

And for the case when t=4 we got:

T(4) =

Part c

For this case we have the following function given:

r(t) =

The derivate is given by:

r'(t) =

The magnitude for the derivate is given by:

|r'(t)| = \sqrt{25e^{10t} +16e^{-8t} +1}

|r'(t)| = \sqrt{25e^{10*4} +16e^{-8*4} +1} =2425825977

And then the tangent vector for this case would be:

T(t) = \frac{}{2425825977}

And for the case when t=4 we got:

T(4) = \frac{1}{2425825977}

5 0
3 years ago
I need help finishing the proof
erastova [34]

Answer:

See proof

Step-by-step explanation:

      Statements                  Reasons

1. \overline{AEC} bisects \angle DAB,\ \angle 1\cong \angle 2   Given

2. \angle 3\cong \angle 4                Definition of angle bisector

3. \overline{AE}\cong \overline{AE}                Reflexive property of equality

4. \triangle ABE \cong \triangle ADE               AAS postulate

5. \overline {AB}\cong \overline{AD}             Congruent triangles have congruent corresponding sides

6. \overline{AC}\cong \overline{AC}                Reflexive property of equality

7. \triangle BAC \cong \triangle DAC                   SAS postulate

8. \overline {BC}\cong \overline{CD}             Congruent triangles have congruent corresponding sides

6 0
3 years ago
Which of the following is equivalent to 24/80
Salsk061 [2.6K]

Answer:

0.3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
inna [77]
(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2
\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
6 0
3 years ago
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