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Luba_88 [7]
2 years ago
7

Sodium is a shiny metal. When cut, it dulls quickly. It also reacts violently with water. Which of the following would probably

show the same characteristics?
Chemistry
1 answer:
siniylev [52]2 years ago
3 0

Answer:

jhgjghjghjghjgjhgjhgjhghjg

Explanation:

i need a crown

You might be interested in
60 POINTS
Juli2301 [7.4K]

Answer:

PBr3 - Molecule , Polar

N2H2 - Molecule , (Polar in E- form and Non- polar in Z form)

C2H2 - Molecule , Non- Polar

N2 - Molecule , Polar

NCl3 - Molecule , Polar

SiF4 - Molecule , Non- Polar

NH3 - Molecule , Polar

F - Not- Molecule (atom)

H2 - Molecule and Non- Polar

Explanation:

Molecule : these are group of two or more atoms joined by strong force of attraction.

H2  is non- polar because it is homoatomic molecule.(made up of same element)

N2 is non- polar because it is homoatomic molecule.

5 0
2 years ago
Gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane (ch4) and liquid water. express your answer as a chemic
laiz [17]
The formula for the compounds in the reaction are as follows with the respective states 
Carbon monoxide - CO (g)
hydrogen - H₂ (g)
methane - CH₄(g)
water - H₂O (l)
reaction of carbon monoxide with hydrogen gas gives rise to methane and water
the balanced chemical equation for the above reaction is as follows
CO(g) + 3H₂(g)  --> CH₄(g) + H₂O(l)
8 0
3 years ago
Describe the differences between polyp and medusa
stealth61 [152]
One difference is that some animals are polyp and some are medusa.


The other difference is that some animals have medusa in their life or polp in their life cycle.


Hope these two differences helps :D
5 0
2 years ago
Uranium – 235 has a half-life of 713 million years. Would uranium – 235 or carbon – 14 be more useful for dating Cambrian time e
kenny6666 [7]
Uranium-235 would be more useful for dating in Cambrian time because Cambrian time was 540 million years ago while the half life of carbon-14 is only 5,730 years
Hope this helps
6 0
2 years ago
Calculate the volumeof 1.0M NaOH necessary to completely neutralize 100mL of 0.50M of phosphoric acid (H3PO4)?
blondinia [14]

Answer:

50 mL

Explanation:

In case of titration , the following formula is used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ =  0.50M

V₁ = 100 mL

M₂ =  1.0M

V₂ = ?

Using the above formula , the volume of base , can be calculated as ,

M₁V₁ = M₂V₂

substituting the respective values ,

0.50M * 100 mL =  1.0M * V₂  

V₂  = 50 mL

3 0
3 years ago
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