What is the final, balanced equation that is formed by combining these two half reactions?
1 answer:
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Answer:
Explanation:
The equation of the reaction is given as:
3H₂ + N₂ → 2NH₃
Given parameters:
Number of moles of NH₃ = 8moles
Number of moles of H₂ = ?
Number of moles of N₂ = ?
Solution
From the balanced reaction equation, we can establish some mole ratios that would help solve the problem:
To find the number of moles of H₂;
The equation shows that:
2 moles of NH₃ were produced using 3 moles of H₂
therefore: 8 moles of NH₃ will be produced by = 12moles
So, 12 moles of hydrogen gas will react to give 8 moles of ammonia.
To find the number of moles of N₂
The equation shows that:
2 moles of NH₃ were produced from 1 mole of N₂
8 moles of NH₃ would be produced from = 4moles of Nitrogen gas
Therefore, 4moles of nitrogen gas would be produced
6.3 × 
In scientific notation, the numerical value without the exponent of 10 must be within the range from 1 to just below 10 (for example, 9.99...). In this case, 6.3 is already within this range, so we just have to multiply it by 1. To get a multiplier of 1 using base 10, we would have to raise 10 to the zeroth power.
In scientific notation, the numerical value without the exponent of 10 must be within the range from 1 to just below 10 (for example, 9.99...). In this case, 6.3 is already within this range, so we just have to multiply it by 1. To get a multiplier of 1 using base 10, we would have to raise 10 to the zeroth power.