What is the final, balanced equation that is formed by combining these two half reactions?
1 answer:
You might be interested in
The final temperature : 78.925°C
<h3>Further explanation </h3>Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Energy releases = 130 kcal = 130 x 4.18 kJ=543.4 kJ
The final temperature :
Final temperature :
ΔT=final-initial
51.925°c=final-27°c
final = 51.925+27=78.925°C
According to Hasselbach-Henderson equation:
Here, is concentration of conjugate base and [HA] is concentration of acid.
In the given problem, conjugate base is and acid is
thus, Hasselbach-Henderson equation will be as follows:
...... (1)
(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 5.06.
(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 4.28.
(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 5.45.
(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 4.76.
(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,
Also,
Putting the values in equation (1),
Therefore, pH of solution is 3.76.