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ELEN [110]
4 years ago
14

What is the pH of a 0.025 M [OH] solution?

Chemistry
1 answer:
Debora [2.8K]4 years ago
8 0
The answer is 12.4.I think its correct answer.

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Cuprite, Cu2O, has a body-centered cubic unit cell of oxide anions with four copper cations in a tetrahedral arrangement around
MrMuchimi

Answer: The coordination number of Cu+ is two while the coordination number of O2- is 4

Explanation:

The coordination number of an ion in a unit cell arrangement refers to the number of immediate neighboring ions of opposite charge surrounding a particular ion. In Cu2O, the charge on Cu is +1 and the charge on the oxide ion is -2. Each copper I ion is surrounded by two oxide ions while each oxide ion is surrounded by four copper I ions in each unit cell.

8 0
4 years ago
A liquid occupies 321ml and has a mass of 376g. what is the density of the liquid?​
oee [108]

Answer:

The density of the liquid is 1.153 grams/ml.

Explanation:

You have to use the fomula of density

density = mass/volume ⇒ density = 376 grams/321 ml ⇒

density = 1.153 grams/ml.

6 0
3 years ago
1. Stan walk 15 km west to the grocery store he shops then walk back 20km east to his house what distance did he cover what was
vitfil [10]

Answer:

His displacement is 0 km because he ends his walk where he started. The total distance of his walk is 20 km because he walks 10 km to the store + 10km back home.

Explanation:

Hope this helps:)

5 0
3 years ago
Independent variable in your own words
Ronch [10]

Explanation:

<em>An</em><em> </em><em>independent</em><em> </em><em>variable</em><em> </em><em>is</em><em> </em><em>defines</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>variable</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>changed</em><em> </em><em>or</em><em> </em><em>controlled</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>scientific</em><em> </em><em>experiment</em><em>. </em>

6 0
3 years ago
PLEASE HELPP
rodikova [14]

Answer:

Option (C) 1 × 10^−12

Explanation:

Step 1:

Data obtained from the question include:

[H+] = 1x10^−2

[OH−] =?

Step 2:

Determination of [OH−] . This is illustrated below:

[H+] x [OH−] = 1x10^-14

1x10^−2 x [OH−] = 1x10^-14

Divide both side by 1x10^−2

[OH−] = 1x10^-14 / 1x10^−2

[OH−] = 1x10^-12

Therefore, the [OH−] of the solution is 1x10^-12

7 0
4 years ago
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