All categories

3 years ago

The power in an electrical circuit is given by the equation P= RR, where /is

Physics

1 answer:

Troyanec [42]3 years ago

7 0

Equation of power in a electrical circuit is given as:

$\bf P = I^2R$

I → Current flowing through the circuit.

R → Resistance of the circuit

We need to calculate power when;

Current (I) = 0.02 A

Resistance (R) = 30 Ω

By substituting values in the equation, we get:

$\rm \longrightarrow P = (0.02)^2 \times 30 \\ \\ \rm \longrightarrow P = 0.0004 \times 30 \\ \\ \rm \longrightarrow P = 0.012 \: W$

$\therefore$ Power in the circuit = 0.012 W

You might be interested in

Its A i did it and i got a

n200080 [17]

Answer:

THATS COOL

Explanation:

4 0

3 years ago

A black hole is a ________

masya89 [10]

Answer:

Answer to the question:

Explanation:

A black hole is a finite region of space within which there is a mass concentration high and dense enough to generate a gravitational field such that no material particle, not even light, can escape it.

8 0

3 years ago

5) When a substance changes its state, all BUT ONE of these statements is true That is A) Mass remains constant B) Only the form

expeople1 [14]

C) kinetic energy changes. Gas>liquid>solid

7 0

3 years ago

In the "before" part of Fig. 9-60, car A (mass 1100 kg) is stopped at a traffic light when it is rear-ended by car B (mass 1400

liq [111]

Complete Question:

In the "before" part of Fig. 9-60, car A (mass 1100 kg) is stopped at a traffic light when it is rear-ended by car B (mass 1400 kg). Both cars then slide with locked wheels until the frictional force from the slick road (with a low ?k of 0.15) stops them, at distances dA = 6.1 m and dB = 4.4 m. What are the speeds of (a) car A and (b) car B at the start of the sliding, just after the collision? (c) Assuming that linear momentum is conserved during the collision, find the speed of car B just before the collision.

Answer:

a) Speed of car A at the start of sliding = 4.23 m/s

b) speed of car B at the start of sliding = 3.957 m/s

c) Speed of car B before the collision = 7.28 m/s

Explanation:

NB: The figure is not provided but all the parameters needed to solve the question have been given.

Let the frictional force acting on car A, $f_{ra} = \mu mg\\$ ............(1)

Since frictional force is a type of force, we are safe to say $f_{ra} = ma$ .......(2)

Equating (1) and (2)

$ma = \mu mg\\a = \mu g\\\mu = 0.15\\a = 0.15 * 9.8 = 1.47 m/s^{2}$

a) Speed of A at the start of the sliding

$d_{A} = 6.1 m\\Speed of A at the start of sliding, v_{A} = \sqrt{2ad_{A} }\\ v_{A} = \sqrt{2*1.47*6.1 } \\v_{A} = \sqrt{17.934 } \\v_{A} = 4.23 m/s$

b) Speed of B at the start of the sliding

$d_{A} = 4.4 m\\Speed of A at the start of sliding, v_{B} = \sqrt{2ad_{B} }\\ v_{B} = \sqrt{2*1.47*4.4 } \\v_{B} = \sqrt{12.936 } \\v_{B} = 3.957 m/s$