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CaHeK987 [17]
2 years ago
8

During destructive interference, two waves moving through the same medium will

Physics
2 answers:
ddd [48]2 years ago
6 0
They will amplify eachother.
Phoenix [80]2 years ago
5 0
It will create a smaller amplitude
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620nm

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Switches, flashers, and similar devices controlling transformers and electronic power supplies shall be rated for controlling in
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Option A - twice

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3 years ago
why is the earth more attracted to the sun gravitational pull than the gravitational pull of the moon
Ierofanga [76]
First, let's take a look at the equation for the force of gravity between two objects:

F = (GMm)/r², where, 

G = gravitational constant = 6.67 x 10⁻¹¹
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m = mass of the other object
r = distance between the two objects

From this equation, we can see that the force of gravity is directly proportional to the mass of the two objects and inversely proportional to the distance between them. We can then say that the Earth is <span>more attracted to the sun than the moon because of the massive mass of the Sun (1.9891 x 10</span>³⁰)<span> compared to moon (7.3577 x 10</span>²²<span>). Although, the moon is nearer to the Earth, it has little effect to bring down the gravitational pull of the Sun. </span>
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3 years ago
S When an uncharged conducting sphere of radius a is placed at the origin of an x y z coordinate system that lies in an initiall
telo118 [61]

The sphere has a constant potential. It is the electric field.

E = V_{0} = 0

In the sphere, then

E_{x} = 0,  E_{y}=0,   E_{z}=0

Outside the sphere, then

V = V_{0} - E_{0}z + \frac{E_{0}a^{3}z}{(x^{2} +y^{2} + z^{2})^{3/2}   }

The elements of the electric field include

E_{x} =\frac{3E_{0}a^{3}xy}{(x^{2} +y^{2} +z^{2})^{5/2}}\\E_{y} = \frac{3E_{0}a^{3}xz}{(x^{2} +y^{2}+z^{2})^{5/2}}

Which becomes,

=E_{0} (1-\frac{a^{3}}{x^{2} +y^{2}+z^{2})^{3/2}}+\frac{3a^{3}z^{2}}{(x^{2} +y^{2}+z^{2})^{5/2}})

<h3>In a consistent electric field, is force constant?</h3>

Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.

If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).

A torque is experienced by an electric dipole (p) in an even electric field (E). The vector cross product of p and E determines the torque's direction.

To learn more about uniform electric field, visit

brainly.com/question/17426130

#SPJ4

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