2: It's not just the capillary action, but the pull from transpiration (the evaporation of water from the tree) that is used to pull water up from the roots.
<span>The second question needs context. Strong bonds alone won't cause tension. I don't see how adhesion is different. High vapour pressure could do it, but it's the difference in pressures that'd cause tension (and the resistance of that pressure by the surface). So, a low and high pressure would be needed. Poorly worded question :( </span>
<span>1: "Adhesion is the tendency of certain dissimilar molecules to cling together due to attractive forces." [1] </span>
<span>3: The other three answere would not work. Think of a boat. </span>
<span>3: If you push gas, it will be compressed(get smaller). If you push liquid it will push something else. Thus, liquids are good for transferring force. This is a hydraulic system.</span>
Answer:
A. The time it takes for the water to boil
It is because salt was added into the water. So the responding variable is the time taken to boil the water.
hope this help u. good luck
Answer:
The rate at which bus 1 is going is 55 mph
The rate at which bus 1 is going is 35 mph
Explanation:
As per the question:
Suppose, the distance traveled by Bus 1 be 'd' at the rate R after a time, t = 3h
Thus
Suppose, the distance traveled by Bus 1 be 'd'' at the rate, R'20 mph slower than the rate of Bus 1 after the same time.
R' = R - 20
The distance is given as the product of rate and time:
d = Rt (1)
Now, the total distance given is 270 miles:
d + d' = 270
Now, using eqn (1):
Rt + R't = 270
3(R + R - 20) = 270
6R = 270 + 60
R = 55 mph
R' = R - 20 = 55 - 20 = 35 mph
M/s2 is the SI of an acceleration.
a couple of things that are necessary to measure this :
- use the timing resources to measure the duty cycle
- performing a computationally intensive division operation
Answer:
356.33 J
Explanation:
Energy: This can be defined as the ability or the capacity to do work. The S.I unit of Energy is Joules (J).
The Energy stored in a capacitor = 1/2CV²
E = 1/2CV².............................. Equation 1.
Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = potential difference across the plates of the capacitor.
Given: C = 10.5 μF = 10.5×10⁻⁶ F, V = 8250 V.
Substitute into equation 1
E = 1/2(10.5×10⁻⁶)(8250)²
E = 357.33 J.
Thus the energy stored in the defibrillator = 356.33 J
