2x + 2y=132
xy=1080
Let x=1080/y
2160/y + 2y=132
2y^2 - 132y +2160=0
2(y^2-66y+1080)=0
2(y-30)(y-33)=0
y=30 or y=33
(36,30) or (30,36)
So... x=30,36 and y=36,30. Either way, the answer is 30 by 36 or 36 by 30.
Answer:
The width of the football field is 160 feet.
The length of the football field is 360 feet.
Step-by-step explanation:
Let w represent width of the football field.
We have been given that the length is 200 ft more than the width, so the length of the field would be
.
We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

Let us solve for w.






Therefore, the width of the football field is 160 feet.
Upon substituting
in expression
, we will get length of field as:

Therefore, the length of the football field is 360 feet.
I believe the answer would be inconsistent and dependent, and also inconsistent and independent. System of equations with three variables are either independent, dependent or inconsistent , each case can be established algebraically and represented graphically.
Four thousand, and eight hundredths.
Answer:
3/5 or 0.6
Step-by-step explanation:
−
5
c
+
16.5
=
13.5
−
5
c
=
−
3
c=3/5
c=0.6