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pogonyaev
3 years ago
13

If a driver makes contact with a steering wheel during a 35 mph crash, she comes to rest in about Δ=15 ms. If, during an identic

al crash, the driver makes contact with an air bag, she comes to rest in about Δ=110 ms. What is the ratio of the force exerted by the steering wheel to the force exerted by the air bag on the driver?
Physics
1 answer:
tatyana61 [14]3 years ago
6 0

Answer:

The ratio of forces is 22 : 3.

Explanation:

Case I:

initial velocity, u = 35 mph

final velocity, v = 0

time, t = 15 ms

Case II:

initial velocity, u = 35 mph

final velocity, v = 0

time, t' = 110 ms

let the mass is m.

According to the Newton's second law, the force is given by the rate of change of momentum.

So

F =\frac{m(v-u)}{t}\\\\F'= \frac{m(v-u)}{t'}\\\\So, \frac{F}{F'} =\frac{t'}{t}\\\\\frac{F}{F'}=\frac{110}{15}=22:3

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Answer:

From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot  find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

E=\frac{F}{Q}

But the force F

F= \frac{kQ1Q2}{r^2}

But the electric field intensity due to a point charge Q at a distance r meters away is given by

E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }

<em>From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases</em>

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3 years ago
On which surface would the toy car travel the farthest?
7nadin3 [17]

Answer:

ice

Explanation:

If the toy car is on a smooth surface, there is less friction. Therefore, the car will most likely go faster. Ice has the least friction so the toy car would travel fast.

7 0
3 years ago
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A block with mass M = 3 kg is moving on a flat surface with constant speed v1 =
Alchen [17]

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5 0
2 years ago
The tread on a tire helps the car hold the road due to A) friction. B) gravity. C) inertia. D) momentum.
NemiM [27]
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8 0
3 years ago
Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are
aliina [53]

Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

Explanation:

The given parameters are;

The mass of the person, m = 65 kg

The height of the person, h = 4.8 m

The speed of the person, v = 8.0 m/s

a) The gravitational potential energy, E_g = m·g·h

Where;

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∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j

Eg = 3,060.72 j

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Ek = 2,080 j

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3 years ago
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