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Alekssandra [29.7K]
3 years ago
9

2075 Set A Q.No. 106 A Carnot engine has 40% efficiency with a sink at 10°C. By how many degrees should the temperature of the s

ource be increased in order to raise the efficiency to 65%?​
Physics
2 answers:
Anni [7]3 years ago
8 0

Answer:

Explanation:

Efficiency of a Carnot engine = 1 – (T2/T1) ;

where T1 = source temperature  and T2 = sink temperature

T2 = 10⁰C = 273+10 = 283K

The initial efficiency = 40%

So 0.4 = 1 - (283/Initial T1)

Initial T1 = 283/(1-0.4) = 471.67 K

 

To raise efficiency to 65%

0.65 = 1 - (283/Increased T1)

Increased T1 = 283/(1-0.65) = 808.57 K

The source temperature must be increased by 808.57 - 471.67 = 336.9 K or 336.9°C.

AlladinOne [14]3 years ago
7 0

Answer:

Explanation:

efficiency of a carnot engine is given by η = 1 – (T2/T1)

where T1 = source temperature , T2 = sink temperature

T2 = 10⁰C = 273+10 = 282 K

Case I: η = 40%

Therefore, η = 40% = 0.4 = 1 - (283/T1)

So, T1 = 283/0.6 = 471.67 K

Case II: η = 65%

Therefore, η = 65% = 0.65 = 1 - (283/T1)

So, T1 = 283/0.35 = 808.57 K

Difference of temps. of case I and case II = 808.57 - 471.67 = 336.9⁰C

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Answer:

the time it will take the element to decay to 1.9 g is 34.8 mins.

Explanation:

Given;

half life of Nitrogen, t = 10 min

initial mass of the element, N₀ = 20 g

final mass of the element, N = 1.9 g

The time taken for the element to decay to final mass is calculated as follows;

time (min)                        mass remaining

0 ----------------------------------20 g

10 mins ------------------------- 10 g

20 mins ------------------------- 5 g

30 mins -------------------------- 2.5 g

40 mins --------------------------- 1.25 g

Interpolate between 2.5 g and 1.25 to obtain the time for 1.9 g

30 min ------------------------- 2.5 g

x ----------------------------------- 1.9 g

40 min -------------------------- 1.25 g

\frac{30 - x}{40- 30} = \frac{2.5 - 1.9}{1.25 - 2.5} \\\\-1.25(30-x) = 6\\\\-37.5 + 1.25x = 6\\\\1.25x = 6+37.5\\\\1.25x = 43.5\\\\x = \frac{43.5}{1.25} \\\\x = 34.8 \ mins

Therefore, the time it will take the element to decay to 1.9 g is 34.8 mins.

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The four tires of an automobile are inflated to a gauge pressure of 2.2 ✕ 105 Pa. Each tire has an area of 0.022 m2 in contact w
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Answer:

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And solving for F we got:

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And replacing we got:

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And if we want the mass we can solve from this formula:

F =mg

With g=9.8 m/s^2 the gravity

Explanation:

For this case we can find the total area of the 4 tires and we got:

A = 4*0.022 m^2 = 0.088m^2

Now we know that the total pressure is:

P=2.2 x10^5 Pa

And then we can find the weight with from this formula:

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And solving for F we got:

F = PA

And replacing we got:

F = 2.2x10^5 Pa * 0.088 m^2 =19360 N

And if we want the mass we can solve from this formula:

F =mg

With g=9.8 m/s^2 the gravity

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