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zimovet [89]
4 years ago
10

The same force is applied to two skateboards. One rolls across the room and the other moves a few feet and comes to a stop. Wher

e was there more work done?
a. The skateboard that traveled the shorter distance shows more work because there was more resistance.
b. The skateboard that traveled the longer distance shows more work because it was lighter.
c. The skateboard that traveled further shows more work because the distance was greater.
d. The skateboard that traveled the shorter distance shows more work because the force was greater.
Physics
2 answers:
podryga [215]4 years ago
8 0

The question and all of the choices are rather messy and misleading.

Here's a simple statement that you can use to make the best match:

If the two forces are equal, then more work is done by the force that
continues to be applied through the greater distance.

mestny [16]4 years ago
6 0

Answer:

<h2>C</h2>

Explanation:

<h2>THIS IS TRUE BECAUSE I TOOK THE TEST, and because THE EQUATION FOR WORK IS WORK = FORCE * DISTANCE AND EVEN THO THEY BOTH HAVE THE SAME FORCE THE OTHER ONE HAS MORE DISTANCE, ITS LIKE SAYING WHICH EQUAION HAS A BIGGER ANSWER 1*1 OR 1*2 WELL ITS OBVIOUSLY THE SECOUND EQUATION SO THE ANSWER IS C LIKE I SAID BEFORE</h2><h2 /><h2>BTW  AL2006 IS WRONG AND I DONT EVEN UNDERSTAND WHAT HE EVEN THO HE IS "TRUSTED"</h2>
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A 63.3 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 35.7 kg boy stands at one end of the board.
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The velocity of the board relative to the ice is zero, since both are at rest.

<h3>What is relative velocity?</h3>

Relative velocity is the velocity of an object in relation to another reference object or point.

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Also, when two objects are at rest, the relative velocity one relative to the other is zero.

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What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa
dlinn [17]

Explanation:

Given that,

Wavelength = 6.0 nm

de Broglie wavelength = 6.0 nm

(a). We need to calculate the energy of photon

Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-9}}

E=3.315\times10^{-17}\ J

(b).  We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}

E=6.709\times10^{-21}\ J

(c). We need to calculate the energy of photon

Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}

E=3.315\times10^{-11}\ J

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}

E=6.709\times10^{-9}\ J

Hence, This is the required solution.

6 0
4 years ago
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