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myrzilka [38]
3 years ago
5

A collection agent earns a fixed amount for each call that he makes, as

Mathematics
1 answer:
White raven [17]3 years ago
4 0

Answer:

The answer is $9.90

Step-by-step explanation:

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Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
Reika [66]
N; n+1; n+2 - 3 consecutive numbers

n(n + 1) = (n + 2)² - 19    |use a(b + c) = ab + ac and (a + b)² = a² + 2ab + b²

n² + n = n² + 4n + 4 - 19    |subtract n² from both sides

n = 4n - 15    |subtract 4n from both sides

-3n = -15    |divide both sides by (-3)

n = 5

n + 1 = 5 + 1 = 6

n + 2 = 5 + 2 = 7

Answer: 5; 6; 7.
6 0
3 years ago
Given no other restrictions, what are the domain and range of the following funtction? f(x)=x^2-2x+2
STALIN [3.7K]

Answer: Domain of the given function is all real numbers.

Range of the given function is {y | y>=1}

Step-by-step explanation:

The given function is a polynomial and the domain of any polynomial is all the real numbers because for any value of x, the function will have some value.

Hence, the domain will be all real numbers.

Range is the set of y values for which the function is defined.

This is a polynomial and to find the range, we will simplify the polynomial.

f(x)=x^2-2x+2\\f(x)=(x-1)^2+1

Therefore, for any value of x, f(x) ≥ 1

Hence, the range becomes {y | y ≥ 1}

8 0
3 years ago
Read 2 more answers
How many of the employees speak spanish but not russians
lora16 [44]

Answer:

more info??

Step-by-step explanation:

5 0
3 years ago
The radio broadcast of AM station KTBC can be heard in the neighboring towns of Waterville and Newport. Of the total number of r
maria [59]

Answer: The required probability is 22.5%.

Step-by-step explanation:

Since we have given that

Probability of radio listeners live in Waterville = 0.75

Probability of radio listeners live in Newport = 0.25

Probability of radio station KTBC in Waterville = 0.20

Probability of radio station KTBC in Newport = 0.30

So, using "Multiplication rule of Probability":

Probability that the listener will be tuned in to station KTBC is given by

0.75\times 0.20+0.25\times 0.30\\\\=0.15+0.075\\\\=0.225\\\\=22.5\%

Hence, the required probability is 22.5%.

6 0
3 years ago
There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
Vikentia [17]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

5 0
4 years ago
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