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Grace [21]
3 years ago
7

Elimination method answer of -7x+4y=-1 and-4x+8y=-12

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0
For the elimination method, you need to have one variable that eliminates and cancel each other out. In this question lets use the variable y. A common denominator for y in the equation would be -8 since we want the variables y to cancel out. We already have 8y for the second equation. Now to get -8y for the first equation we need to multiply everything by -2 this would leave us with 14x+-8y=2. Now all you have to do is add the two equations. 10x=-10. So the final answer for x is -1. To find y just substitute the x value in the first equation which would give you y=-2. See that wasn't so hard:))
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2h/3 -1/4 = 1/3<br>how do you do this problem​
mrs_skeptik [129]
Subtract from both sides
7 0
3 years ago
Can someone help please
devlian [24]

the answer is x=47 hope this helps

3 0
3 years ago
a skier is trying to decide whether or not to buy a season ski pass. A daily pass costs $61. A season ski pass costs $300. The s
Oksana_A [137]
D=61d+30d=91d, 

S=300+30d

S<D

300+30d<91d

300<61d

d>4.91  Since days are integers,

The skier would have to go at least 5 days to make the season pass less expensive than using the daily pass.
4 0
3 years ago
Solve -7 - | x- 6| = - 12
andrezito [222]

Answer:

x=54/ 7 , 30/7

Step-by-step explanation:

x=54/ 7 , 30/7

5 0
3 years ago
Read 2 more answers
The amount of soda in a 16-ounce can is normally distributed with a mean of 16 ounces and a standard deviation of .5 ounce. What
Firdavs [7]

Answer:

Probability that a randomly selected can will have less than 15.5 ounces is 0.1587.

Step-by-step explanation:

We are given that the amount of soda in a 16-ounce can is normally distributed with a mean of 16 ounces and a standard deviation of 0.5 ounce.

<em>Let X = amount of soda</em>

So, X ~ N(\mu=16,\sigma^{2} =0.5^{2})

The z-score probability distribution for normal distribution is given by;

               Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean amount = 16 ounces

            \sigma = standard deviation = 0.5 ounce

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, the probability that a randomly selected can will have less than 15.5 ounces is given by = P(X < 15.5 ounces)

  P(X < 15.5 ounces) = P( \frac{  X -\mu}{\sigma} < \frac{ 15.5-16}{0.5} ) = P(Z < -1) = 1 - P(Z \leq 1)

                                                                 = 1 - 0.8413 = 0.1587

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.</em>

Hence, the probability that a randomly selected can will have less than 15.5 ounces is 0.1587.

3 0
4 years ago
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