Answer:
41 students
Step-by-step explanation:
20% of 205 is 41
Y = 2x^2 - 13x + 5
dy/dx = 4x - 13
At x = 3, dy/dx = 4(3) - 13 = 12 - 13 = -1
and y = 2(3)^2 - 13(3) + 5 = 2(9) - 39 + 5 = 18 - 34 = -16
The tangent line at x = 3, passes through the point (3, -16) and has a slope of -1
y - (-16) = -1(x - 3)
y + 16 = -x + 3
y = -x - 13 is the required equation.
The critical values of the function are x = 0 and x = 64
The critical values of a function f(x) are the values of x for which f'(x) = 0.
Given,
f(x) = 
The derivative is found as follows, applying the quotient rule:
f'(x) = ![\frac{[5(x^{4} )(x-8)^{2}-5x^{4} [(x-8)^{2} ]' }{[5(x-8)^{2} ]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B5%28x%5E%7B4%7D%20%29%28x-8%29%5E%7B2%7D-5x%5E%7B4%7D%20%5B%28x-8%29%5E%7B2%7D%20%5D%27%20%7D%7B%5B5%28x-8%29%5E%7B2%7D%20%5D%5E%7B2%7D%20%20%7D)
= 
The zeros of the function are the zeros of the numerator, thus:

x - 64 = 0------------->x = 64
The critical values are x = 0 and x = 64
Learn more about critical values here:brainly.com/question/12958088
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11.05
14.60
46.00
71.65 is your answer