Answer:
I would buy the 2000 Toyota Tundra. Yes it is the most expensive, but it is the newest so it should require less expense money for problems, it is a manual transmission 6 cylinder so it should get better gas mileage, and it has fewer miles. The rankings of these trucks are not provided, however a Toyota tundra is considered to be a workhorse in the truck. If this is an opinion question, that's my choice.
Step-by-step explanation:
Answer:
x = 35
Step-by-step explanation:
Solve for x:
6 x - 15 = 4 x + 55
Hint: | Move terms with x to the left hand side.
Subtract 4 x from both sides:
(6 x - 4 x) - 15 = (4 x - 4 x) + 55
Hint: | Combine like terms in 6 x - 4 x.
6 x - 4 x = 2 x:
2 x - 15 = (4 x - 4 x) + 55
Hint: | Look for the difference of two identical terms.
4 x - 4 x = 0:
2 x - 15 = 55
Hint: | Isolate terms with x to the left hand side.
Add 15 to both sides:
2 x + (15 - 15) = 15 + 55
Hint: | Look for the difference of two identical terms.
15 - 15 = 0:
2 x = 55 + 15
Hint: | Evaluate 55 + 15.
55 + 15 = 70:
2 x = 70
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 2 x = 70 by 2:
(2 x)/2 = 70/2
Hint: | Any nonzero number divided by itself is one.
2/2 = 1:
x = 70/2
Hint: | Reduce 70/2 to lowest terms. Start by finding the GCD of 70 and 2.
The gcd of 70 and 2 is 2, so 70/2 = (2×35)/(2×1) = 2/2×35 = 35:
Answer: x = 35
x= -8/5
x equals negative 8 over 5
Answer:
Express s in terms of v and t
s= v/t, multiplying both sides of the equation by t
Express t in terms of v and s
t= s/v ( from s=vt)
Step-by-step explanation:
Your question is incomplete, but I am guessing that it reads something like:
“Diego has run 4/5 of a race distance. He has run 7 2/3 miles. How long is the race? Or “how many miles does he have left?”
How long is the race? = 9 7/12 miles
4/5x = 7 2/3
4/5x = 23/3
x = 23/3 • 5/4
x = 115/12
x = 9.58333
x = 9 7/12 miles
How many miles does he have left? = 1 1/12 miles
1/5 • 115/12 = 115/60 = 1.916666
= 1 55/60 = 1 11/12 miles
Let me know if I didn’t guess your question correctly and I will try to help more.
