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3 years ago

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At a local river there were 48 alligators laying on the river bank. If 5/6 of the alligators were sleeping, how many were NOT as

leep? PLEASE ANSWER QUICKLY ILL LOVE YOU FOREVER

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:The answer is 40.

Step-by-step explanation:

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I want to know the answer to this . I don’t really get it . so how would I get the answer ?

Lapatulllka [165]

Answer:

0.444... (or 44.44...%)

Step-by-step explanation:

The experimental probability is the probability of an event actually happening. The experimental probability of a man having a beard here is 44.444...% (8/18).

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3 years ago

Natalie is making doll customers. Each costume has 4 buttons that coast 3 € each and a zipper that costs 7€. How much does she s

otez555 [7]

24euro on zipper
and 24euro on button

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3 years ago

6/5 ÷ ____ = 6<br><br> A. 1/5<br> B. 30 <br> C. 1/30<br> D. 5

murzikaleks [220]

Answer:

A. $\displaystyle \frac{1}{5}$

Step-by-step explanation:

$\displaystyle \frac{6}{5} \div \frac{1}{5} = 6 \\ \\ OR \\ \\ \frac{6}{5} \div 6 = \frac{1}{5}$

I am joyous to assist you anytime.

4 0

3 years ago

A gumball machine consists of a base and a glass sphere. The gumballs are stored in the glass sphere. If each

V125BC [204]

Answer:

6 gumballs can be stored in the gumball machine.

Step-by-step explanation:

Since a gumball machine consists of a base and a glass sphere, and the gumballs are stored in the glass sphere, if each gumball has a diameter of 1.5 inches, to determine how many gumballs can be stored in a gumball machine whose glass sphere measures 10 inches in diameter, the following calculation must be made:

10 / 1.5 = X

6.666666 = X

Thus, 6 gumballs can be stored in the gumball machine.

5 0

3 years ago

The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

5 0

3 years ago