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3 years ago

11

At a local river there were 48 alligators laying on the river bank. If 5/6 of the alligators were sleeping, how many were NOT as

leep? PLEASE ANSWER QUICKLY ILL LOVE YOU FOREVER

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:The answer is 40.

Step-by-step explanation:

You might be interested in

Evaluate: <img src="https://tex.z-dn.net/?f=3-2%5E2%2B4%2A3%2B5" id="TexFormula1" title="3-2^2+4*3+5" alt="3-2^2+4*3+5" align="a

earnstyle [38]

Answer:

16

Step-by-step explanation:

Apply PEMDAS:

Solve the exponent, multiply from left to right, and then subtract and add from left to right.

$3-2^2+4*3+5\\\\3-4+4*3+5\\\\3-4+12+5\\\\-1+12+5\\\\11+5\\\\\boxed{16}$

8 0

3 years ago

Read 2 more answers

Arlene writes this problem:

fredd [130]

it looks like its answers two, four, and five.

tell me how you did !

5 0

3 years ago

Solve the formula V=pir^2h for r <br><br> PLEAASSSEEE HELP

otez555 [7]

Answer:

B

Step-by-step explanation:

So we have the formula:

$V=\pi r^2h$

And we want to solve it for r.

So, let's first divide both sides by π and h. This will cancel out the right side:

$r^2=\frac{V}{\pi h}$

Now, take the square root of both sides:

$r=\sqrt{\frac{V}{\pi h}}$

And we're done!

Our answer is B.

I hope this helps!

7 0

3 years ago

Read 2 more answers

Expand the given power by using Pascal’s triangle. (9a - 10b)^6

xxMikexx [17]

Answer:

$531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

Step-by-step explanation:

1 n=0

1 1 n=1

1 2 1 n=2

1 3 3 1 n=3

1 4 6 4 1 n=4

1 5 10 10 5 1 n=5

1 6 15 20 15 6 1 n=6

This is where n is the exponent in

$(x+y)^n$ .

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

Now we want to expand:

$(9a-10b)^6$ or we we can rewrite as $(9a+(-10b))^6$ .

Let's replace $x$ with $(9a)$ and $y$ with $(-10b)$ in the expansion:

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

$((9a)+(-10b))^6$

$=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6$

Let's simplify a bit:

$=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6$

$=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

8 0

3 years ago

Evaluate Integral: 2sin(2x) from 0, pi/2

Neko [114]

Integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2

8 0

3 years ago