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vladimir1956 [14]
3 years ago
8

4/5(20e - 5q) - 1/9(-27q + - 18e)help

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0

Answer: =−q+48.929073 <-- coming frm a calculator lol

Step-by-step explanation:

Likurg_2 [28]3 years ago
4 0

Answer:

−q+48.929073

Step-by-step explanation:

Let's simplify step-by-step.

4/5 ((20)(2.718282)−5q)−19

(−27q+(−18)(2.718282))

Distribute:

=(4/5)((20)(2.718282))+(4/5)(−5q)+3q+5.436564

=43.492509+−4q+3q+5.436564

Combine Like Terms:

=43.492509+−4q+3q+5.436564

=(−4q+3q)+(43.492509+5.436564)

=−q+48.929073

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Flauer [41]

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

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Area of triangle:

A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2

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2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

a+2b = 11 cm  ⇒  2b = 6 cm   ⇒  b = 3 cm

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A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2

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A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

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p = 32:2 = 16 cm

A=\sqrt{16(16-8)(16-12)^2}\\\\ A=\sqrt{16\cdot8\cdot4^2}\\\\ A=\sqrt{2\cdot8\cdot8\cdot4^2}\\\\ A=8\cdot4\cdot\sqrt2\\\\ A=32\sqrt2\ cm^2\approx45.2548\ cm^2

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How many millimeters are in 100 cm
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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