<em>Greetings from Brasil...</em>
Let's add all the values on one side and make it equal to the sum of all the other values on the other side
(- X) + (- X) + (- X) + (- X) + (- X) + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = X + X + X + (- 1) + (- 1) + (- 1) + (- 1) + (- 1) + (- 1) + (- 1) + (- 1)
- 5X + 12 = 3X - 8
- 5X - 3X = - 8 - 12
- 8X = - 20 x(- 1)
8X = 20
X = 20/8
<h2>X = 5/2</h2>
<em>or X = 2.5</em>
Answer:
The first option
Step-by-step explanation:
If you look at the graph, you'll realize that when x = 2 in the first graph, y = 4
Answer:
26 + y
----------
9y
Step-by-step explanation:
Your using parentheses here would remove a great deal of ambiguity. Looking at your 8-y/3y + y+2/9y - 2/6y, I have interpreted it to mean:
(8-y)/3y + (y+2)/9y - (2/6)y. For example, without parentheses, your 8-y/3y might be interpreted differently, as 8 - y/(3y), or 8 - 1/3.
Looking at (8-y)/3y + (y+2)/9y - (2/6)y again, we see three different denominators: 3y, 9y and 6 y. The LCD here is 9y. Multiplying all three terms of (8-y)/3y + (y+2)/9y - (2/6)y by the LCD, we get:
3(8-y) + (y+2) + 3y. We must now divide this by the LCD:
3(8-y) + (y+2) + 3y
--------------------------
9y
Next we need to perform the indicated multiplication:
24 - 3y + y + 2 + 3y
----------------------------
9y
and then to combine like terms:
24 + 2 - 3y + y + 3y, 26 + y
---------------------------- or -----------
9y 9y
\left[x _{1}\right] = \left[ \frac{2}{3}+\left( \frac{-1}{3}\,i \right) \,\sqrt{2}\right][x1]=[32+(3−1i)√2] totally answer
