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-BARSIC- [3]
1 year ago
15

What is the midpoint of (-23,-14) and (-18,2)

Mathematics
1 answer:
zloy xaker [14]1 year ago
7 0

Given two coordinates point 1 as (-23,-14) and point 2 as(-18,2).

To find the midpoint we would use the formula below;

\text{midpoint(x,y)}=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Where x1=-23, x2=-18, y1=-14, y2=2

We would substitute the values into the midpoint formula.

\begin{gathered} \text{midpoint =(}\frac{-23-18}{2},\frac{-14+2}{2}) \\ =(-\frac{41}{2},-6) \end{gathered}

Therefore, the answer is

\text{midpoint}=(-\frac{41}{2},-6)

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Answer:

10^5

Step-by-step explanation:

the reason is because you move the decimal to the right 5 times, which is the positive direction.

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1.625

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3 years ago
Multiply.
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The multiplication of the expression (x² + 3x + 2) (2x² + 3x + 1) is 2x⁴ + 9x³ + 14x² + 9x + 2

<h3>Multiplication</h3>

(x² + 3x + 2) (2x² + 3x + 1)

= 2x⁴ + 3x³ + x² + 6x³ + 9x² + 3x + 4x² + 6x + 2

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= 2x⁴ + 3x³ + 6x³ + x² + 9x² + 4x² + 3x + 6x + 2

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8 0
1 year ago
Identify the expression as a numerical expression or variable expression I•8
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3 years ago
Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S(12, 5)
valentina_108 [34]

Answer:

The area of the parallelogram is 55 square unit.

Step-by-step explanation:

The area of a parallelogram is

A=\frac{1}{2}\times base\times height

It is given that the vertices of the parallelogram are  P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).

Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.

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A=\frac{1}{2}\times 11\times 10

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