Jordan wants to play a basketball game at a carnival. The game costs the player $ 5 $5dollar sign, 5 to play, and the player get
s to take two long-distance shots. If they miss both shots, they get nothing. If they make one shot, they get their $ 5 $5dollar sign, 5 back. If they make both shots, they get $ 10 $10dollar sign, 10 back. Jordan has a 40 % 40%40, percent chance of making this type of shot. Here is the probability distribution of X = X=X, equals the number of shots Jordan makes in a randomly selected game, and M = M=M, equals the amount of money Jordan gains from playing the game. X = # of shots made X=# of shots madeX, equals, \#, start text, space, o, f, space, s, h, o, t, s, space, m, a, d, e, end text 0 00 1 11 2 22 M = money gained M=money gainedM, equals, start text, m, o, n, e, y, space, g, a, i, n, e, d, end text − $ 5 −$5minus, dollar sign, 5 $ 0 $0dollar sign, 0 $ 5 $5dollar sign, 5 Probability 0.36 0.360, point, 36 0.48 0.480, point, 48 0.16 0.160, point, 16 Calculate the mean of X XX. μ X = μ X =mu, start subscript, X, end subscript, equals shots made
means both p and q must hold;
means either p or q must hold.
is 0;