Answer:
-10,-6,4,3,7
Step-by-step explanation:
negatives are backwords the higher it gets the smaller the value
Answer:
7.4
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
(5)
Since ∠EBA = 90° then ∠ABD = 90° ( straight angle ) and
∠ABC + ∠CBD = ∠ABD, that is
2x + 3x - 10 = 90, simplifying
5x - 10 = 90 ( add 10 to both sides )
5x = 100 ( divide both sides by 5 )
x = 20, thus
∠ABC = 2x = 2 × 20 = 40°
∠CBD = 3x - 10 = (3 × 20) - 10 = 60 - 10 = 50°
(6)
4x - 18 = 3x + 7 ( vertical angles are congruent )
Subtract 3x from both sides
x - 18 = 7 ( add 18 to both sides )
x = 25
7y = 5y + 28 ( vertical angles are congruent )
Subtract 5y from both sides
2y = 28 ( divide both sides by 2 )
y = 14
I think you mean circumference...Area is
. We have the area so we need to use it to solve for the radius which we will then use in the circumference formula.
. Divide both sides by pi to get
. Of course the simplification of the left side gives us
and r = 4. Now fill that in to the circumference formula, which is
, to get C
which is a circumference of
Answer:
<h2><u><em>
6. </em></u></h2><h2><u><em>
a. 11 and 2/3 yds. squared</em></u></h2><h2 /><h2><u><em>
b. Yes, the volume of the shed is 11 and 1/3 yards squared and what she's trying to put into it is only 10 yards squared, if put in properly, it will be able to fit.</em></u></h2><h2 /><h2><u><em>
7. 1,110 in. squared</em></u></h2>
Step-by-step explanation:
6.
a.
(10/3)*(14/9)*(9/4)
= 11 2/3
b.
Yes, because the volume of the shed is about 11.67 yards long, the 10 yards of wood will fit in the shed.
7.
For this one, we have to break it into two pieces.
(I made them into a small box and and big box)
The measurements of the small box are 7*5*6.
The measurements of the big box are 20*5*9.
Using this information, we can make the following equation and solve it quickly.
(7*5*6) + (20*5*9)
(210) + (900)
1,110
Thus, the volume of this box is 1,110 in. ^2
