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DENIUS [597]
3 years ago
8

How many moles are in 25.58 grams of H20? SHOW WORK

Chemistry
1 answer:
kirill115 [55]3 years ago
7 0

Answer:

1.42 moles

Explanation:

25.58 g of H₂O .

Molecular weight of water = 2 x 1 + 16 = 18

1 mole of water = 18 g of water

18 g of water = 1 mole

25.58 g of water = 25.58 / 18 mole

= 1.42 moles .

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If element x forms the oxides xo and x2o3 the oxidation numbers of element x are
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Hello,

In this case, given the molecular formulas:

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An analytical chemist is titrating of a solution of nitrous acid with a solution of . The of nitrous acid is . Calculate the pH
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The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>

<em />

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That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:

NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻

HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂

It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:

pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]

pH = 3.35 + log₁₀ [0.03900mol] / [0.17964mol]

<h3>pH = 2.69</h3>
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