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devlian [24]
3 years ago
9

A 8 g object displaces 50 mL of water. What is its specific gravity?

Chemistry
2 answers:
DaniilM [7]3 years ago
6 0

The specific of gravity is 0.16

Hope this helps :)

Phoenix [80]3 years ago
5 0

Answer:

he is right it is 0.16

Explanation:

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Jaką maksymalną ilość gramów azotanu (V) potasu można rozpuscic w 300g wody w temperaturze 90 C
olga2289 [7]

Answer:

  • <u>609g </u>

<u></u>

Explanation:

The translated question is:

<em>What maximum amount of grams of potassium nitrate (V) can be dissolved in 300g of water at 90 °C</em>

<em></em>

<h2>Solution</h2>

<em></em>

To answer the question you need to consultate the solubiity information for potassium nitrate (V), KNO₃.

The attached table contains the solutibility table for KNO₃ at different temperatures.

At 90ºC it is 203g / 100g water.

Then, to calculate the <em>maximum amount of grams of potassium nitrate (V) that can be dissolved in 300g of water at 90 °C</em>, just multiply by the amount of water:

  • 203g / 100g water × 300 g water = 609g ← answer

6 0
3 years ago
mastering biology ch 3 Water molecules have a polarity, which allows them to be electrically attracted to other water molecules
aniked [119]

Answer:

The answer to your question is: hydrogen bonding

Explanation:

Hydrogen bonding is a kind of interaction dipole-dipole, that means that 2 molecules attract each other because the have partial charges.

In the picture we can see 4 molecules of water, red circles are oxygens and white circles are hydrogens. In this bonding, Oxygen due to its size, and atomic number is more electronegative than hydrogen, then in water molecule is formed a partial negative charge in oxygen and a partial positive charge in hydrogen.

Finally, because of this partial charge, one oxygen can bond to one hydrogen of another molecule.

7 0
3 years ago
Which statement best applies collision theory to preventing a dangerous reaction from occurring?
puteri [66]
There is no answer choices i need answer choices you said which i cant say which one it is if i dont have answer choices
4 0
3 years ago
Read 2 more answers
How many grams of kbr must be dissolved to make 25.0 ml of a solution that has a molarity of 0.85 m?
lyudmila [28]
Molarity is defined as the number of moles of solute in 1 L of solution 
molarity of solution to be prepared is 0.85 M
this means that there should be 0.85 mol of KBr in 1 L of solution 
if 1 L contains - 0.85 mol
then 25.0 mL should contain - 0.85 mol / 1000 mL x 25.0 mL = 0.0213 mol 
mass of KBr - 0.0213 mol x 119 g/mol = 2.53 g
mass of KBr that should be dissolved in 25.0 mL is 2.53 g

4 0
3 years ago
A buffer solution contains 0.306 M C6H5NH3Br and 0.418 M C6H5NH2 (aniline). Determine the pH change when 0.124 mol HCl is added
Ulleksa [173]

<u>Answer:</u> The pH change of the buffer is 0.30

<u>Explanation:</u>

To calculate the pH of basic buffer, we use the equation given by Henderson Hasselbalch:

pOH=pK_b+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})

pOH=pK_b+\log(\frac{[C_6H_5NH_3^+]}{[C_6H_5NH_2]})        .....(1)

We are given:

pK_b = negative logarithm of base dissociation constant of aniline  = 9.13

[C_6H_5NH_3^+]=0.306M

[C_6H_5NH_2]=0.418M

pOH = ?

Putting values in equation 1, we get:

pOH=9.13+\log(\frac{0.306}{0.418})\\\\pOH=8.99

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH_{initial}=14-8.99=5.01

To calculate the molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles hydrochloric acid solution = 0.124 mol

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of HCl}=\frac{0.124}{1L}\\\\\text{Molarity of HCl}=0.124M

The chemical reaction for aniline and HCl follows the equation:

                   C_6H_5NH_2+HCl\rightarrow C_6H_5NH_3^++Cl^-

<u>Initial:</u>           0.418        0.124           0.306

<u>Final:</u>             0.294          -                0.430

Calculating the pOH by using using equation 1:

pK_b = negative logarithm of base dissociation constant of aniline  = 9.13

[C_6H_5NH_3^+]=0.430M

[C_6H_5NH_2]=0.294M

pOH = ?

Putting values in equation 1, we get:

pOH=9.13+\log(\frac{0.430}{0.294})\\\\pOH=9.29

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH_{final}=14-9.29=4.71

Calculating the pH change of the solution:

\Delta pH=pH_{initial}-pH_{final}\\\\\Delta pH=5.01-4.71=0.30

Hence, the pH change of the buffer is 0.30

8 0
3 years ago
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