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3 years ago

Question 4 How many carbon-carbon triple bonds are present in a molecule of 4,5-diethyloctane?

Chemistry

1 answer:

ivann1987 [24]3 years ago

5 0

Answer:

We will have zero bonds

Explanation:

In this case, we have to start with the structure of 4,5-diethyloctane. This name ends with the suffix "ane" therefore we have an alkane. All the alkanes are made with single bonds between carbons and single bonds between carbon and hydrogen.

The molecule will have a carbon chain of eight carbons and we will have 2 branches, one ethyl on carbon 4 and another ethyl on carbon 5. (see figure 1)

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At constant temperature the pressure on a 6.0 L sample of a gas is reduced from 2.0 atm to 1.0 atm. What is the new volume of th

kotegsom [21]

P1V1=P2V2, so P1V1/P2=V2.
2atm x 6.0 L/1.0 atm = 12.0 L
The new volume would be 12.0 Liters

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3 years ago

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1.For the reaction P4 O10(s) + 6H2O(l) → 4H3PO4(aq), what mass of P

Alex17521 [72]

P₄O₁₀ + 6H₂O → 4H₃PO₄
The equation shows us that the molar ratio of
P₄O₁₀ : 6H₂O = 1:6

We also know that one mole of a substance contains 6.02 x 10²³ particles. We can use this to calculate the moles of water.
moles(H₂O) = (5.51 x 10²³) / (6.02 x 10²³)
= 0.92 mole
That means moles of P₄O₁₀ = 0.92 / 6
= 0.15

Each mole of P₄O₁₀ contains 4 moles of P.
moles(P) = 4 x 0.15 = 0.6 mol
Mr of P = 207 grams per mol
Mass of P = 207 x 0.6
= 124.2 grams

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3 years ago

Read 2 more answers

A cylinder of oxygen gas has a pressure of 6.00 atm at 25.0

Readme [11.4K]

P1/T1=P2/T2 Gal Lussac's Law
25 C= 298K (just add 273)
0 C= 273 k

6.00atm/298=P2/273

P2=5.50 atm

4 0

3 years ago

Electrochemistry - Equilibrium

Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K

E⁰cell = 1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298 lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298 lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

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3 years ago

How many moles of carbon are in 3.5 L?

SashulF [63]

Answer:

0.16mole

Explanation:

To solve this problem, we are going to assume that the number of moles of carbon to be determined is that at STP, standard temperature and pressure.

The number of moles of a substance at STP is given as;

Number of moles = $\frac{volume}{22.4}$

Given volume = 3.5L

Now, insert the parameters;

Number of moles = $\frac{3.5}{22.4}$ = 0.16mole

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3 years ago