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Vlada [557]
2 years ago
11

They all have the same choices but one of them its not gonna be used.​

Chemistry
1 answer:
Dima020 [189]2 years ago
3 0

Answer:

limiting reactant

Explanation:

it is consumed totally

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What are nanochemicals and what are there uses?
NARA [144]

Nanochemicals can be defined as chemicals generated by using nanomaterials (materials that possess of size on nanometer dimensions). The nanochemicals are used in multiple different applications including chemical warfare, bicycle making, armor design and military weapons crafting. The most commonly used and observed nanochemicals are carbon nanotubes that are used a ton in industry for applications such as stronger materials (stronger bicycles).

Smart materials are exquisitely designed materials whose property(ies) can be modified with the use of an external stimulus such as temperature, stress, pH, and so on. Some examples of smart materials include shape memory materials, piezoelectric materials, ferrofluids, self-healing materials, and such. Applications involve memory pillows, memory based solar panels (for satellites), light sensitive glasses, and so on.

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6 0
3 years ago
Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.00 M lactic acid and 25.0 mL of 0.50 M sodium lactate.
max2010maxim [7]

From the calculations, the pH of the buffer is 3.1.

<h3>What is the pH of the buffer solution?</h3>

The  Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

Amount of the salt = 25/1000 *  0.50 M = 0.0125 moles

Amount of the acid = 75/1000 *  1.00 M = 0.075 moles

Total volume = ( 25 + 75)/1000 = 0.1 L

Molarity of salt = 0.0125 moles/0.1 L = 0.125 M

Molarity of the acid = 0.075 moles/0.1 L = 0.75 M

Given that the pKa of lactic acid is 3.86

pH = 3.86 + log( 0.125/0.75)

pH = 3.1

Learn more about pH:brainly.com/question/5102027

#SPJ1

6 0
2 years ago
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
The component which dissolves in a solution is called the?
VladimirAG [237]

The correct answer is Solute

Explanation:

In chemistry, a solution refers to a homogenous mixture of two substances that occurs through dissolution, this means once they are mixed the substances form a uniform new substance and cannot be easily separated. Additionally, in chemistry, the substances involved in a solution are either classified as solutes if they are the substances that dissolve to form a solution or as solvents in the case of substances in which the solute dissolves in. For example, if you mix salt and water, the salt acts as the solute while the water is the solvent. Thus, the component which dissolves in a solution is called the solute.

5 0
3 years ago
Which statement describes a physical change? *
xxMikexx [17]
B. The surface of a silver cup turns black when it is exposed to air.
4 0
3 years ago
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