Answer: The answer is NO.
Step-by-step explanation: The given statement is -
If the graph of two equations are coincident lines, then that system of equations will have no solution.
We are to check whether the above statement is correct or not.
Any two equations having graphs as coincident lines are of the form -
If we take d = 1, then both the equations will be same.
Now, subtracting the second equation from first, we have
Again, we will get the first equation, which is linear in two unknown variables. So, the system will have infinite number of solutions, which consists of the points lying on the line.
For example, see the attached figure, the graphs of following two equations is drawn and they are coincident. Also, the result is again the same straight line which has infinite number of points on it. These points makes the solution for the following system.
Thus, the given statement is not correct.
Let x= the number of books purchased: 7 books purchased
let y = the number of toys purchased;10 toys purchased
Equations: x+y=17
6x+11y=152 x+10=17
-6(x+y=17) y=10 -10 -10
------------
-6x-6y=-102 x=7
6x+11y=152
--------------------
0x+5y=50
---- ----
5 5
Answer:
josh vendió 17 libros recaudando 306 dolares .
jessica vendió 255 libros recaudando 4590 dolares.
Step-by-step explanation:
Sustituimos por variables :
libros que vendió Jessica = x
libros que vendió Josh = y
entonces:
x + y = 272
Jessica vendió 15 veces mas libros que josh:
x = 15y
Reemplazamos en la anteriior ecuacion:
15y +y = 272
16y = 272
y = 17
Reemplazamos en la primela ecuacion :
x + 17 = 272
x = 255
Answer:
Step-by-step explanation:
The formula for determining the the volume of a rectangular base pyramid is expressed as
Volume = 1/3 × base area × height
From the information given,
Length of base = 9 cm
Width of base = 4.6 cm
Area of base = 9 × 4.6 = 41.4 cm²
Volume of pyramid = 82.8cm³
Therefore
82.8 = 1/3 × 41.4 × height
82.8 = 13.8 × height
Dividing both sides of the equation by 13.8, it becomes
height = 82/13.8
Height = 5.94 8 cm
In the 
direction we consider the 
subintervals [0, 1] and [1, 2] (each with length 1), while in the 
direction we consider the 
subintervals [0, 2] and [2, 4] (with length 2). Then the lower right corners of the cells in the partition of 
are (1, 0), (2, 0), (1, 2), (2, 2).
Let 
. The volume of the solid is approximately
###
More generally, the lower-right-corner Riemann sum over 
and 
subintervals would be
Then taking the limits as 
and 
leaves us with an exact volume of 
.
