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Serga [27]
4 years ago
7

Math help, (again) These are mainly for corrections

Mathematics
2 answers:
dsp734 years ago
7 0

Answer:

D

Step-by-step explanation:

Because if you multiple 7 from 1,2,3,4 you can get all y answers like 7,14,21 and 28. HERE

7*1=7

7*2=14

7*3=21

7*4=28.

e-lub [12.9K]4 years ago
4 0

The answer would be the last option. :)

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Step-by-step explanation:

Solve by elimination

\begin{bmatrix}x-5y=35\\ 3x-6y=51\end{bmatrix}

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= 3x-15y=105

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-\underline{3x-15y=105}

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4 years ago
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Step-by-step explanation:

In most cases, we can factor a polynomial, or quadratic, by looking at the factors of the last term.  In this case, the last term is \frac{1}{4}.  When we factor a polynomial, we are looking for two expressions that when multiplied together using FOIL (forward-outside-inside-last) will give us the polynomial.  For example: (a + b)(a + b) or (a+ b)².

In order to get y² + y + \frac{1}{4}, we are looking for a 'c' value that will add up to '1' which is our 'b' value (ay² + by + c).

Since \frac{1}{2}*\frac{1}{2}=\frac{1}{4}and\frac{1}{2}+\frac{1}{2}=1

Then, we can use \frac{1}{2} as our factor for both expressions.  Putting this together we get:  (y + \frac{1}{2})(y + \frac{1}{2}) or (y + \frac{1}{2})²

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