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3 years ago

PLEASE HELP NOW I ONLY NEED TO KNOW NUMBER 5. 25 POINTS!!!

Mathematics

1 answer:

Anika [276]3 years ago

7 0

If Point C and D are equidistant from point A, it means that AC and AD are of the same length. AC = AD

AC = AD (S) (<span>Points C and D are equidistant from point A)
</span>AE = AE (S) (The two triangle shared the same side)
∠CAE = ∠EAD (A) (This angle is between the two sides that we just proved to be equal)

By SAS,
ΔEAD ≡ ΔEAC

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In the figure shown below, AC is parallel to DE with transversal BF

densk [106]

Answer:

<em><u>Given </u></em><em><u>-</u></em><em><u> </u></em> AC is parallel to DE

angle 3y + 28 = angle X ( Vertically opposite angles are equal).

3y + 28 = X

X + Y = 180° ( supplementary angles).

3y - X = (-28)

Solving both the equation we get

multiply eq 1 with 3

3x + 3y = 540

-X + 3y = (-28)

subtracting

4x = 568

x = 142°

3y + 28 = 142

3y = 142 - 28

3y = 114

y = 38°

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2 years ago

If an airplane descends 15 feet every 1.45 seconds, how far would the airplane travel in three and a half minutes? The equation

NemiM [27]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

$\qquad \sf \dashrightarrow \: \dfrac{15}{1.45} \: \: ft / sec$

Now we have to calculate the descent in 3.5 minutes ~

$\qquad \sf \dashrightarrow \: \dfrac{15}{1.45} \: \: \times 3.5 \times 60$

$\qquad \sf \dashrightarrow \: 2172.41 \: \: ft$

So, the airplane descends 2172.41 feels in three and a half minutes ~

5 0

2 years ago

What's the lowest common multiple of of 2.2 and 5

alexira [117]

Hey there, just multiply 2.2 by 5, 2.2×5=11. Therefore, the lowest common multiple of 2.2 and 5 is 11.

8 0

3 years ago

Write the point-slope form of an equation of the line through the points (-7, 7) and (4, 1).

seraphim [82]

Answer:

Choice B. $\displaystyle y - 7 = -\frac{6}{11} \, (x + 7)$ .

Step-by-step explanation:

Start by finding the slope of this line. Let $(x_1,\, y_1)$ and $(x_2,\, y_2)$ represent two distinct points on a line on a Cartesian Plane. (That is, $x_1 \ne x_2$ .) The slope of this line would be:

$\displaystyle \frac{y_2 - y_1}{x_2 - x_1}$ .

For the line in this question:

$x_1 = -7$ ,
$y_1 = 7$ ;

$x_2 = 4,$
$y_2 = 1$ .

Indeed, $x_1 \ne x_2$ . The slope of this line would thus be $\displaystyle \frac{1 - 7}{4 - (-7)}$ , which is equal to $\displaystyle -\frac{6}{11}$ .

On a Cartesian Plane, the point-slope form of a line that has a slope of $m$ and includes the point $(x_0,\, y_0)$ can be written as:

$y - y_0 = m\, (x - x_0)$ .

(Note the minus signs in this form.)

For the line in this question, $m = \displaystyle -\frac{6}{11}$ . There are two equivalent expressions for its point-slope form:

Using the first point, $y - 7 = \displaystyle -\frac{6}{11}\, (x - (-7))$ . This equation is equivalent to $y - 7 = \displaystyle -\frac{6}{11}\, (x + 7)$ .
Using the second point, $y - 1 = \displaystyle -\frac{6}{11}\, (x - 4)$ .

7 0

3 years ago

Ellen is at a hydroplane boat show starting from 1.0 miles away the boat drives toward her and then passes her the boat travels

navik [9.2K]

The 40 seconds and 50

8 0

3 years ago