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Setler79 [48]
3 years ago
10

PLEASE HELP NOW I ONLY NEED TO KNOW NUMBER 5. 25 POINTS!!!

Mathematics
1 answer:
Anika [276]3 years ago
7 0
If Point C and D are equidistant from point A, it means that AC and AD are of the same length. AC = AD

AC = AD (S) (<span>Points C and D are equidistant from point A)
</span>AE = AE (S)  (The two triangle shared the same side)
∠CAE = ∠EAD (A) (This angle is between the two sides that we just proved to be equal)

By SAS, 
 ΔEAD ≡ ΔEAC

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Simplify.<br> (2 - 61) - (-10 + 4i)
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Answer:

− 49 − 4 i

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A motorcycle daredevil is planning a stunt to perform at a county fair. A ramp must be built to give him a 20%
Shkiper50 [21]

Answer: 95 feet

Step-by-step explanation:

Let the length of the horizontal run be represented by x.

Slope Grade = (Rise/Run) × 100

20 = (19/x) × 100

20 = 1900/x

20x = 1900

x = 1900/20

x = 95

Therefore, the length of the horizontal run must be 95 feet

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3 years ago
Sin^2A+cos^2A=? .find the value. ​
d1i1m1o1n [39]

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3 0
3 years ago
Divide 2/7÷1/3 what is the answer I need help please help me
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7 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
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