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Vilka [71]
3 years ago
11

what does pre-image mean ? like when your using a graph & they ask “what the preimage of (4,2) what does that mean ?

Mathematics
1 answer:
enyata [817]3 years ago
5 0
The image before the transformation
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*HIGHER POINTS* Solve for m<A​
Musya8 [376]

Answer:

The answer should be about 114.

Step-by-step explanation:

Of you look at the shape of the other angles. B and D seem to be about 90 and the shape of A is just a little bit bigger than ninety. I started by adding 78, 90, and 90 together which gave me 246. Then I subtracted 246 from 360 which gave me 114. I had estimated the answer to be around 110.

6 0
2 years ago
What radius of a circle is required to inscribe a regular hexagon with an area of 210.44 cm2 and an apothem of 7.794 cm
alekssr [168]
We know that

[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²

[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm

the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
8 0
3 years ago
The line plot shows the number of miles Scarlet walked each day last week. What is the total number of miles Scarlet walked last
AveGali [126]
<span>12 <span>1/2</span></span><span> miles that the answer I'm probably late 


</span>
5 0
3 years ago
Read 2 more answers
PLEASE ANSWER WILL GIVE BRAINLIEST
torisob [31]

Answer:

volume of box = l*b*h

= 8/9*5/12*3/10

= 1/9 cubic feet

Step-by-step explanation:

3 0
2 years ago
Compute each sum below. If applicable, write your answer as a fraction.
Alex777 [14]

Answer:

First equation is -425

Second equation is 11.25

Step-by-step explanation:

First equation we can write as

\sum_{i=0}^7 5 \times (-2)^i

computing

When i=0 -> 5 \times (-2)^0 =5

When i=1 -> 5 \times (-2)^1 = -10

...

When i=7 -> 5 \times (-2)^7 = --640

then replacing each term we have

5  + (-10) + ( 20) + ( -40) +  (80) +( -160) +   320 + (-640) = -425

For the second equation we'll have 9 terms, solving in a similar fashion

When i=1 -> \frac{1}{4}1=0.25

When i=2 -> \frac{1}{4}2=0.50

When i=3 -> \frac{1}{4}3=0.75

...

When i=9 -> \frac{1}{4}9=2.25

So we have 0.25 + 0.50 + 0.75 + 1.00 + 1.25 + 1.50+ 1.75 +2.00 +2.25

4 0
3 years ago
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