Please take 1 minute, and really read the example solution
under problem #12. All of the other eight problems on the
sheet are solved in exactly the same way:
Multiply each side of the equation by the denominator of
the fraction ... the number under the variable (the letter).
This easy step will get you the answer to each of the
eight problems.
I can't help noticing that the title of the sheet is 'extra PRACTICE' .
If someone handed you the answers, then you would not get the
practice. That would be just like stealing from you, and would be
just plain mean.
Answer:
D. 60
Step-by-step explanation:
To find an equal number of numbers the sum has to be equal to 6*x.
You need to make a draw of the problem to understand what to do.
The height of the pyramid, and half the original base side length make a rectangle triangle, whose hypothenuse is the height of the lateral area of one of the pyramids faces, so we have. So we use Pythagoras:
hyp^2 = 11^2 + 14^2 = 317
hyp = 17.8 m
that is the height of the lateral area triangle
Now to find the area of the lateral area triangle, we have:
a = base*height/2 = 22*17.8/2
a = 195.8 m^2
that is the lateral area of the pyramid, 196 m^2
Answer:

Step-by-step explanation:
See attachment for graph
First, we need to take any corresponding values of x and y


Next, we calculate the slope (m)




Next, we calculate the line equation using:



Make y the subject

Hence, the line equation is:
