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vodka [1.7K]
3 years ago
14

What is the average rate of change of the function

Mathematics
1 answer:
masha68 [24]3 years ago
7 0

Answer:

2

Step-by-step explanation:

The average rate of change is the slope of the linear function f(x)

Given

f(x) = 2x + 8 ← in the form y = mx + c

with slope m = 2

Then average rate of change = 2

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Which is the better buy? 5-pack of toaster pastries for $4.13 or 9-pack of toaster pastries for $7.56
kolbaska11 [484]

Answer: <em>The answer is </em><u><em>9-pack of toaster pastries for $7.56</em></u>

Step-by-step explanation:

<em>Basicly it would be more expensive if you bought 9 for the first option but less for the other.</em>

5 0
3 years ago
One of the legs of a right triangle measures 9 cm and the other leg measures 16 cm.
aalyn [17]

Answer:

18.4 cm

Step-by-step explanation:

Using Pythagoras rule:

Hypotenuse =

\sqrt{9 ^{2}  + 16 ^{2} }

= 18.4 cm

7 0
3 years ago
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
Need help with this question
OverLord2011 [107]

Given: a quadratic function with vertex (2,3) opening upward .

Find: the given statement is true or false.

Explanation: if parabola has a vertex at (2,3) and opens upward, it has one real solution., (2,3) will be a lowest point. The vertex will be at lowest point, it will be minimum.

that means graph has no one real solution. hence it will never going to intersect. so this statement is false.

Final answer: the given statement is FALSE.

7 0
1 year ago
3 1/2 divided by 1/4
yuradex [85]

Answer:

Have a great day

Step-by-step explanation:

=3 1/2÷1/4

=7/2×4

=7×2

=14

5 0
2 years ago
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