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3 years ago

The gravitational attraction between two masses of 3kg that are separated by a distance of 1cm is

Physics

1 answer:

Luba_88 [7]3 years ago

6 0

Answer:

6.003×10¯⁶ N

Explanation:

We'll begin by converting 1 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

1 cm = 1 cm × 1 m / 100 cm

1 cm = 0.01 m

Finally, we shall determine the gravitational attraction. This can be obtained as follow:

Mass 1 (M₁) = 3 Kg

Mass 2 (M₂) = 3 Kg

Distance apart (r) = 0.01 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 3 × / 0.01²

F = 6.003×10¯¹⁰ / 1×10¯⁴

F = 6.003×10¯⁶ N

Thus the gravitational attraction is 6.003×10¯⁶ N

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To find the answer, we have to know more about the ideal diode.

<h3>What is an ideal diode?</h3>

A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another.
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<h3>How to find the current in ideal diode?</h3>

Here we have given with the values,

$V_2=65V\\V_1=0V\\R_1=490Ohm.$

We have the expression for current in mA of the ideal diode with forward biased voltage drop as,

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