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miv72 [106K]
3 years ago
7

The gravitational attraction between two masses of 3kg that are separated by a distance of 1cm is

Physics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

6.003×10¯⁶ N

Explanation:

We'll begin by converting 1 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

1 cm = 1 cm × 1 m / 100 cm

1 cm = 0.01 m

Finally, we shall determine the gravitational attraction. This can be obtained as follow:

Mass 1 (M₁) = 3 Kg

Mass 2 (M₂) = 3 Kg

Distance apart (r) = 0.01 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 3 × / 0.01²

F = 6.003×10¯¹⁰ / 1×10¯⁴

F = 6.003×10¯⁶ N

Thus the gravitational attraction is 6.003×10¯⁶ N

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What does the diameter in meters need to be of a round parachute that the designer has determined needs to have an area of 500 s
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Area of a circle is
A= pi r^2
so
500m^2 = 3.14 r2
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square root both sides
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d=2r
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to 3 sig fig
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