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Gre4nikov [31]
3 years ago
7

Two massive, positively charged particles are initially held a fixed distance apart. When they are moved farther apart, the magn

itude of their mutual gravitational force changes by a factor of n. Which of the following indicates the factor by which the magnitude of their mutual electrostatic force changes?
a. 1/n2
b. 1/n
c. n
d. n2
Physics
1 answer:
Aneli [31]3 years ago
6 0

c. n

The magnitude of the gravitational force is given by Newton's law of universal gravitation:

F_g=-G\frac{m_1m_2}{d^2}

Here G is the gravitational constant, m_1, m_2 are the masses of the particles and d is the distance between them.

The magnitude of the electrostatic force is given by Coulomb's law:

F_e=k\frac{q_1q_2}{d^2}

Here k is the Coulomb constant, q_1, q_2 are the chargues of the particles and d is the distance between them.

As can be seen, both forces are inversely proportional to the square of the distance. Thus, the factor is the same in both cases.

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3 years ago
Silver has a density of 9.32 g/cm cubed. find the length of one side of a 184 g silver cube
Olin [163]

Answer: 2.70 cm

Given:

Density, d=9.32 g/cm^{3}

Mass, m=184 g

Formula Used:

Volume, V = density/mass

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