Answer:
how is that a question?
Explanation:
yeah i dunno the answer cause thats not a question
Answer:
0.4113772 s
Explanation:
Given the following :
Mass of bullet (m1) = 8g = 0.008kg
Initial horizontal Velocity (u1) = 280m/s
Mass of block (m2) = 0.992kg
Maxumum distance (x) = 15cm = 0.15m
Recall;
Period (T) = 2π√(m/k)
According to the law of conservation of momentum : (inelastic Collison)
m1 * u1 = (m1 + m2) * v
Where v is the final Velocity of the colliding bodies
0.008 * 280 = (0.008 + 0.992) * v
2.24 = 1 * v
v = 2.24m/s
K. E = P. E
K. E = 0.5mv^2
P.E = 0.5kx^2
0.5(0.992 + 0.008)*2.24^2 = 0.5*k*(0.15)^2
0.5*1*5.0176 = 0.5*k*0.0225
2.5088 = 0.01125k
k = 2.5088 / 0.01125
k = 223.00444 N/m
Therefore,
Period (T) = 2π√(m/k)
T = 2π√(0.992+0.008) / 233.0444
T = 2π√0.0042910
T = 2π * 0.0655059
T = 0.4113772 s
I’m pretty sure the answer is C. Any change of state or movement requires energy
Answer:
h=4r
Explanation:
To solve the problem it is necessary to apply the energy conservation equations for the roller coaster.
The energy conservation equations warn that:

Where,
Kinetic Energy
Potential Energy
Equating,

Re-arrange for V,

For balance of forces, according to the announcement, those who are on a roller coaster can withstand up to a maximum of 9g.
Therefore, considering the centripede speed and the speed of the fall, we obtain that,


The centripetal acceleration is given by the equation

Where
V = Tangencial velocity
r = Radius
Then replacing in the equation of Force,





Therefore the maximum height of the incline if the cars starts from the rest is 4 times the raidus of the inclination
Newton’s 3rd Law: for every action there is an equal but opposite reaction.
Assuming that the box is motionless, we can say the force is -20N