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iogann1982 [59]
3 years ago
9

Three mountain climbers set out to climb a mountain from the same altitude and all arrive at the same location at the top. Mount

ain climber A took a long gradual slope to the top, B went a steeper but shorter path, and C tackled the sheer straight side to the top. Assume all three climbers have the same mass. Which climber gained the greatest potential energy?A. AB. BC. CD. all did the same amount of work
Physics
1 answer:
Vikki [24]3 years ago
8 0

Answer:All did same amount of work

Explanation:

All three mountain climbers took different routes to reach the peak. There is a constant gravity force acting on the object i.e. gravity force. Gravity force is conservative i.e. work done by a conservative force is independent of the path followed.

Therefore work done by all the mountain climbers is the same i.e. all did the same amount of work.

                               

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8. An airplane is flying at 200 m/s when it touches the ground at the airport. It has a constant negative acceleration, and slow
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Given

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Required

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A 94 g particle undergoes SHM with an amplitude of 8.3 mm, a maximum acceleration of magnitude 7.8 x 103 m/s2, and an unknown ph
Lelechka [254]

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a) T = 6.49*10^-3 s

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Amplitude of the particle, A = 8.3 mm = 8.3*10^-3 m

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the equation describing Simple Harmonic Motion is given as

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Velocity = dx/dt = -Aw sin(wt + φ)

Acceleration = d²x/dt = -Aw² cos(wt + φ)

From the question, we were given, magnitude of acceleration to be 7.8*10^3 m/s²

Aw² = 7.8*10^3

w² = 7.8*10^3 / A

w² = 7.8*10^3 / 8.3*10^-3

w² = 939759

w = √939759

w = 969

Recall, T = 2π/w, so that

T = (2 * 3.142) / 969

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Maximum speed = 8.3*10^-3 * 969

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mgx + 1/2mx² =

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x = A cos(wt + φ)

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