Answer:
Explanation:
Work done by torque is given as
Word one = torque × angular displacement
W = τ × θ
Given that,
τ = 2000Nm
Mass of motor = 300kg
Radius r = 55cm = 0.55m
Work done by wheel in first t= 23second.
Now we need to find the angular displacement
We know that,
τ = I•α
Moment of inertia of wheel
I = MR²
I = 300 × 0.55²
I = 90.75 kgm²
Then, τ = I•α
α = τ / I
α = 2000/90.75
α = 22.04rad/s²
Then, using circular motion,
∆θ = wit + ½αt²
wi = 0rad/s
∆θ = ½αt²
∆θ = ½ × 22.04 × 23²
∆θ = 5829.2 rad.
Then,
Work done?
W = τ × θ
W = 2000 × 5829.2
W = 1.17 × 10 ^7 J
Answer:
0 m/s²
Explanation:
Since each skater pushes the other with a force of 70 N, according to Newton's third law, there is an equal reaction and thus the other pushes back with a force of 70 N in the other direction, so we have forces of +70N and -70 N respectively. So, the net force on each skateboarder is F = + 70 N + (-70 N) = + 70 N - 70 N = 0 N.
Since force, F = ma where a = acceleration and m = mass,
a = F/m.
So, since for each skater, F = 0N,
a = 0 N/m
= 0 m/s²
So, the acceleration of each skater is 0 m/s²
"<span>There can only be one voltage supplied" is the statement among the statements given in the question that true regarding DC current. The correct option among all the options that are given in the question is the second option or option "B'. I hope the answer comes to your help.</span>
Acceleration can be any change in speed, increasing or decreasing.
You haven't said whether the ball is speeding up or slowing down.
If its acceleration is positive ... speed is increasing ... then in 2.5 seconds,
it GAINS (0.5 m/s² x 2.5 sec) = 2.5 m/s of speed. Added to its initial
speed of 2.0 m/s, it ends up moving at 4.5 m/s.
If its acceleration is negative ... speed is decreasing ... then in 2.5 seconds,
it LOSES (0.5 m/s² x 2.5 sec) = 2.5 m/s of speed. Added to its initial
speed of 2.0 m/s, it ends up moving at -0.5 m/s. That means that it ends up
moving in the opposite direction compared to its direction at the beginning of
the change.