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3 years ago

If you speed up from rest to 12m/s in 3 seconds, what is your acceleration?

2 answers:

7 0

The answer id 4 m/s/s this is because 12/3 = 4 and an easy way to get the units is put the two together

Acceleration = m/s (Meters per second)
Time = s (Seconds)

m/s/s = Meters per second/ Per second

boyakko [2]3 years ago

6 0

b) 4m/s/s

This is because you divide the speed you reach, by the time it takes to get to that speed:

12m/s ÷ 3s = 4m/s/s

The units come from what you divide, meters per second ÷ seconds this can be written as m/s/s or ms-²

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If an atom has seven electrons how many are in the second shell?

Ostrovityanka [42]

<span>5 electrons because first shell can only have two electrons and second can hold up until 8</span>

6 0

3 years ago

Read 2 more answers

La masa de un objeto en la tierra es de 100 kg.

andreev551 [17]

Answer:

a) 980 N

b) 100 kg

c) 163.33 N

Explanation:

The weight of the object on Earth is the product of its mass times the acceleration due to gravity, that is:

$W=m\,g=(100\,\,kg)\,g=(100\,\,kg)\,(9.8\,\,m/s^2)=980\,\,N$

The mass of the object on the moon, is exactly the same (100 kg) since mass is an inherited value of the object.

Considering that the acceleration of gravity on the Moon is about 1/6 that we have on earth (g), then the weight of the object on the Moon becomes:

$W=m\,\frac{g}{6} =\frac{980}{6}\,\,N=163.33\,\,N$

3 0

3 years ago

A copper wire is 1.6 m long and its diameter is 1.1 mm. If the wire hangs vertically, how much weight (in N) must be added to it

qaws [65]

Answer:

Weight required = 194.51 N

Explanation:

The elongation is given by

$\Delta L=\frac{PL}{AE}$

Length , L= 1.6 m

Diameter, d = 1.1 mm

Area

$A=\frac{\pi d^2}{4}=\frac{\pi \times (1.1\times 10^{-3})^2}{4}=9.50\times 10^{-7}m^2$

Change in length, ΔL = 2.8 mm = 0.0028 m

Young's modulus of copper, E = 117 GPa = 117 x 10⁹ Pa

Substituting,

$\Delta L=\frac{PL}{AE}\\\\0.0028=\frac{P\times 1.6}{9.50\times 10^{-7}\times 117\times 10^9}\\\\P=194.51N$

Weight required = 194.51 N

8 0

3 years ago

The mysterious visitor that appears in the enchanting story The Little Prince was said to come from a planet that "was scarcely

FromTheMoon [43]

Answer:

Part a)

$g = 1 \times 10^{-5} m/s^2$

Part b)

$v = 0.011 m/s$

Explanation:

Part a)

As we know that the acceleration due to gravity is given as

$g = \frac{GM}{R^2}$

$g = \frac{G(\frac{4}{3}\pi R^3 \rho)}{R^2}$

$g = \frac{4}{3}\pi \rho G R$

now we know that

$\rho = \frac{M}{\frac{4}{3}\pi R^3}$

$\rho = \frac{5.98 \times 10^{24}}{\frac{4}{3}\pi (6.37 \times 10^6)^3}$

$\rho = 5523.2 kg/m^3$

now we have

$g = \frac{4}{3}\pi (5523.2) (6.67 \times 10^{-11})(6.5)$

$g = 1 \times 10^{-5} m/s^2$

Part b)

As we know that the escape speed is given as

$v = \sqrt{\frac{2GM}{R}}$

$v = \sqrt{2gR}$

$v = \sqrt{2(1\times 10^{-5})(6.5)}$

$v = 0.011 m/s$

8 0

3 years ago

When water freezes, its volume increases by 9.05% (that is, equation). What force per unit area is water capable of exerting on

PIT_PIT [208]

Answer:

1.991 × 10^(8) N/m²

Explanation:

We are told that its volume increases by 9.05%.

Thus; (ΔV/V_o) = 9.05% = 0.0905

To find the force per unit area which is also pressure, we will use bulk modulus formula;

B = Δp(V_o/ΔV)

Making Δp the subject gives;

Δp = B(ΔV/V_o)

Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²

Thus;

Δp = 2.2 × 10^(9)[0.0905]

Δp = 1.991 × 10^(8) N/m²

3 0

3 years ago